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...mol ions / 1 mol Mg3(C6H5O7)2) x (0.082057338 L atm/

**K**mol) x (37 + 273)**K**= 29.5 atm1 Answers · Science & Mathematics · 15/09/2019

...from condensing the vapor (113 J/(

**K**⋅mol)) x (78.4 - (-17.0))**K**x (0.445 mol) = 4797.189 J = 4.797 kJ from cooling the liquid to -17.0 ∘**C**0.558 kJ + 17.159 kJ + 4.797 kJ = 22.5 kJ total1 Answers · Science & Mathematics · 09/09/2019

...torr. The temperature must be in ˚

**K**. To convert ˚**C**to ˚**K**, add 273˚ T1 = 18.6 + 273 = 291.6˚**K**T2 = -32...2 Answers · Science & Mathematics · 08/09/2019

...987 atm) x (3.87 L) / ((0.082057338 L atm/

**K**mol) x (25 + 273)**K**) = 0.1562 mol CO2 (0.1562 mol CO2) (1 mol**C**/ 1 mol CO2) × (12.01078 g**C**/mol) = 1.876 g**C**(1.300 g ...1 Answers · Science & Mathematics · 04/09/2019

Thermochemistry .... q = moles x molar heat capacity x ΔT + moles x molar heat of vaporization q = 1.056 mol x 0.1124 kJ/molK x 25K + 1.056 mol x 38.56 kJ/mol q = 43.7 kJ The 2015 kJ comes from using 48.7...

3 Answers · Science & Mathematics · 27/08/2019

(21.56 + 273.15)

**K**x (767 mmHg / 725 mmHg) = 311.7829**K**(311.7828**K**- 273.15**K**) = 38.63°**C**4 Answers · Science & Mathematics · 06/08/2019

... E° = (8.314 J/molK x 298K / 4 / 96,458

**C**/mol) ln 9.82x10^-8 E° = -1.04V The negative cell potential ...1 Answers · Science & Mathematics · 07/08/2019

...the pressure and volume are inversely proportional: PV =

**k**. The product of the pressure and volume should be the same... = -0.803 / 0.003 ....... when P = 0 T = -268**C**Percent error = |(-273 - (-268)) / -273| x 100 = 1.83% .2 Answers · Science & Mathematics · 03/08/2019

... constant and cancel it .. (4) plug and chug.... remember T must be absolute..

**K**or R.. never °**C**nor °F you do that and you don't need to remember boyles law, charles...3 Answers · Science & Mathematics · 31/07/2019

(38.6 + 273.15)

**K**x (0.798 L / 4.64 L) x ((125 kPa x 7.50062 torr/kPa) / 685 torr) = 73.385**K**= -200.°**C**2 Answers · Science & Mathematics · 26/07/2019

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