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  1. ...mol ions / 1 mol Mg3(C6H5O7)2) x (0.082057338 L atm/K mol) x (37 + 273) K = 29.5 atm

    1 Answers · Science & Mathematics · 15/09/2019

  2. ...from condensing the vapor (113 J/(K⋅mol)) x (78.4 - (-17.0))K x (0.445 mol) = 4797.189 J = 4.797 kJ from cooling the liquid to -17.0 ∘C 0.558 kJ + 17.159 kJ + 4.797 kJ = 22.5 kJ total

    1 Answers · Science & Mathematics · 09/09/2019

  3. ...torr. The temperature must be in ˚K. To convert ˚C to ˚K, add 273˚ T1 = 18.6 + 273 = 291.6˚K T2 = -32...

    2 Answers · Science & Mathematics · 08/09/2019

  4. ...987 atm) x (3.87 L) / ((0.082057338 L atm/K mol) x (25 + 273) K) = 0.1562 mol CO2 (0.1562 mol CO2) (1 mol C / 1 mol CO2) × (12.01078 g C/mol) = 1.876 g C (1.300 g ...

    1 Answers · Science & Mathematics · 04/09/2019

  5. Thermochemistry .... q = moles x molar heat capacity x ΔT + moles x molar heat of vaporization q = 1.056 mol x 0.1124 kJ/molK x 25K + 1.056 mol x 38.56 kJ/mol q = 43.7 kJ The 2015 kJ comes from using 48.7...

    3 Answers · Science & Mathematics · 27/08/2019

  6. (21.56 + 273.15) K x (767 mmHg / 725 mmHg) = 311.7829 K (311.7828 K - 273.15 K) = 38.63°C

    4 Answers · Science & Mathematics · 06/08/2019

  7. ... E° = (8.314 J/molK x 298K / 4 / 96,458 C/mol) ln 9.82x10^-8 E° = -1.04V The negative cell potential ...

    1 Answers · Science & Mathematics · 07/08/2019

  8. ...the pressure and volume are inversely proportional: PV = k. The product of the pressure and volume should be the same... = -0.803 / 0.003 ....... when P = 0 T = -268 C Percent error = |(-273 - (-268)) / -273| x 100 = 1.83% .

    2 Answers · Science & Mathematics · 03/08/2019

  9. ... constant and cancel it .. (4) plug and chug.... remember T must be absolute.. K or R.. never °C nor °F you do that and you don't need to remember boyles law, charles...

    3 Answers · Science & Mathematics · 31/07/2019

  10. (38.6 + 273.15) K x (0.798 L / 4.64 L) x ((125 kPa x 7.50062 torr/kPa) / 685 torr) = 73.385 K = -200.°C

    2 Answers · Science & Mathematics · 26/07/2019

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