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...that

**C**= 2 and Y = 5. In summary, M = 0 L = 1**C**= 2**K**= 3 Y = 5 J = 7 V = 8 N = 9 The equation...1 Answers · Science & Mathematics · 06/05/2010

...28 +

**c****c**= 6k - 10 12k = 28 + 6k - 10 6k = 18**k**= 3**c**= 6(3) - 10**c**= 8**k**+**c**= 3 + 8 = 111 Answers · Science & Mathematics · 11/01/2009

Use the Binomial Theorem: (1 + x)^n = ∑(

**k**= 0 to n)**C**(n,**k**) x^**k**. Let x = -1: 0 = ∑(**k**= 0 to n)**C**(n,**k**) (-1)^**k**...1 Answers · Science & Mathematics · 05/02/2014

... X. This corresponds to the product

**C**(n,**k**)⋅**C**(n-**k**,r-**k**). Every such pair of subsets A,B is...4 Answers · Science & Mathematics · 27/07/2013

By the Binomial Theorem, (1 + x)^n = sum(

**k**=0 to n)**C**(n,**k**) x^**k**. Differentiating both sides twice, we get n(n - 1) (1 + x...1 Answers · Science & Mathematics · 19/10/2009

-3/8 =

**k**/**c**-3c = 8k**c**= -8k/3**k**/ (1 + b - 8k/3) = undefined 1 + b - 8k...4b = 8k/3 - 48/3 b = (2k - 12) / 3 8k + 3 = 2k - 12 6k = -15**k**= -2.5 b = (-5 - 12)/3 b = -17/3**c**= -8k / 3**c**= 20/3 y = -2.5 / (x^2 - 17x/3 + 20/3) y = -7...1 Answers · Science & Mathematics · 08/11/2009

Solving for

**k**from x/**k**-**c**/w = y add**c**/w to both sides x/**k**= y +**c**/w x/**k**= (wy+**c**)/w cross multiply**k**(wy+**c**) = wx divide both sides by (wy+**c**)**k**= wx/(wy+**c**)1 Answers · Science & Mathematics · 23/01/2013

...respectively. Reference (2) gives formulas for h=-b/2a and

**k**=**c**- [(b^2)[(4a)]. Using these we answer the questions that h = -(-12)/[2...1 Answers · Science & Mathematics · 21/02/2013

Notice that y =

**k**(x - a)^2 +**c**has its vertex at x = a, so the point (a, b) is the parabola...0) lies on the parabola, so plugging in x = y = 0 yields: 0 =**k**(0 - a)^2 + b = ka^2 + b ==>**k**= -b/a^2. Thus, the equation of the parabola...1 Answers · Science & Mathematics · 22/11/2012

This has to be mis-stated.

**k**(mod**c**) is a constant, so if a +**k**= b +**k**(mod**c**) then we can subtract**k**from both...1 Answers · Science & Mathematics · 27/06/2012

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