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  1. Use the binomial probability formula. P(X = k) = C(n,k) * p^k * q^(n-k) n : number of trials (10) k : number...

    3 Answers · Science & Mathematics · 31/12/2016

  2. ... to fix the unity element? i.e. Is ϕ(1_F) = 1_K ? (c) Is {0} a subring of Q? If you said (a) yes; (b) yes...

    1 Answers · Science & Mathematics · 27/07/2016

  3. ...have ln(e^5) = k*2 + C. So we get ln(e^5) is 5, and 5 = 2*k + C. With y(5) = e^2, we get 2 = 5*k + C. Solving the 2 ...

    2 Answers · Science & Mathematics · 24/07/2016

  4. Reinsert your brain properly, kid. You'll be more coherent, then.

    4 Answers · Entertainment & Music · 22/06/2016

  5. You want us to do that without first defining a, k, c, or d? Followup: Your definitions answer your question...

    1 Answers · Science & Mathematics · 22/09/2018

  6.   This is a linear relationship: C = K − 273 K = C + 273 1. 77°K = 77−273 = −196°C 2. 0°C = 0+273 = 273°K

    1 Answers · Science & Mathematics · 29/04/2016

  7. ...and h. You can see the latter as follows: f(x) = c . a^(d(x-h)) + k = c . a^(dx) . a^(-dh) + k = c' . a^(dx) + k, where c' = c . a^(-dh) So we...

    2 Answers · Science & Mathematics · 06/04/2016

  8. ...be considered a double application of Pascal's rule: C(n,k) = C(n-1,k-1) + C(n-1,k) = C(n-2,k-2) + C(n-2,k-1) + C...

    2 Answers · Science & Mathematics · 28/03/2016

  9. => f(x) = x^2 - kx + 5 a = 1 b = -k c = 5 b^2 - 4ac = 0 => only one zero. y^2 - 4*1*5 = 0 y^2 = 20 y = ±2√5

    1 Answers · Education & Reference · 21/03/2016

  10. ...reverse for the metal: ∆H = mc∆T 2501 J = (14.0 g) c (73.3 K) c = 2.44 J/g/K

    1 Answers · Science & Mathematics · 10/02/2016

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