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  1. ...be considered a double application of Pascal's rule: C(n,k) = C(n-1,k-1) + C(n-1,k) = C(n-2,k-2) + C(n-2,k-1) + C...

    2 Answers · Science & Mathematics · 28/03/2016

  2. y= A cos (θ -d ) K + c A= amplitude , d horizontal shift, c= vertical shift, k = frequency per 2π or 360...

    1 Answers · Science & Mathematics · 20/03/2011

  3. Let C(n,k) be the binomial coefficient n!/k!(n-k)! (C(n,k) is the number of ways to select k things from...

    1 Answers · Science & Mathematics · 30/07/2009

  4. ... Chris = C So basically: J + K = 19 K + C = 14 J + C = K 1) Use substitution postulate: it means...

    1 Answers · Science & Mathematics · 09/02/2009

  5. ...*. The binomial probability formula is: P(X = k) = C(n,k) * p^k * q^(n-k) n : number of trials (10) k : number...

    3 Answers · Science & Mathematics · 09/01/2019

  6. ...that’s what you mean Multiplying both sides by k: Ek = kc Subtract k from both sides: Ek – k = -c Factoring...

    2 Answers · Science & Mathematics · 16/01/2015

  7. Use the binomial probability formula. P(X = k) = C(n,k) * p^k * q^(n-k) n : number of trials (10) k : number...

    3 Answers · Science & Mathematics · 31/12/2016

  8. ...solution is y(x) = c*e^(6i*x) + k*e^(-6i*x) + C. Now y(0) = c + k + C = -6. Next, y'(x) = 6i*c*e^(6i*x) - 6i*k*e^(-6i*x), so y'(0) = 6i...

    1 Answers · Science & Mathematics · 24/02/2013

  9. ... first roll. Binomial probability formula: P(X=k) = C(n,k) * p^k * q^(n-k) p = 1/6 q = 5/6 n = number of dice ...

    2 Answers · Science & Mathematics · 28/03/2018

  10. ... to use the notation of C(n,k), where: C(n,k) = n! / ((n-k)! k!) C(40,4) = 40 x 39 x 38 x 37 / (4 x 3 x 2 x 1) = 91390 ways PART...

    2 Answers · Science & Mathematics · 04/10/2014

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