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(x - h)^2 + (y -

**k**)^2 = r^2 (6 - h)^2 + (5 -**k**)^2 = r^2 (-3 - h)^2 + (2 -**k**)^2 = r^2 (-2 - h)^2 + (1 -**k**)^2 = r^2 (6 - h)^2 + (5 -**k**)^2 = (-3 - h...6k = 0 48 - 18 - 6k = 0 30 - 6k = 0 6k = 30**k**= 30/6**k**= 5 (6 - 1)^2 + (5 - 5)^2 = r^2...2 Answers · Science & Mathematics · 09/09/2019

... and 2 points. Set up a system of equations, solve for

**c**and**k**, then find T(0) 415 = 75 +**c*** e^(-10k) 340 =**c*** e^(-10k) 347 = 75 +**c*** e^(-20k...2 Answers · Science & Mathematics · 04/09/2019

(a) domain of f (-∞, ∞) (b) range of f [-1,∞) (

**c**) x-intercepts : 2 and 4 (d) y-intercept : 8 (e) f ...at x=3 (i) the relative minimum of f is -1 (j) f(-4) = 8 (**k**) The values of x for which f(x)=3 are 1...2 Answers · Science & Mathematics · 06/09/2019

...' is b The distance from (h ,

**k**) to**C**and**C**' is**c**(x - h)^2 + (y -**k**)^2...5 (4.5 , 4.5) is the center of rotation. h^2 +**k**^2 = a^2 4.5^2 + 4.5^2 = a^2 2 * 4.5^2 = a^2 4.5...2 Answers · Science & Mathematics · 18/08/2019

...b Here are a few other examples:

**c**= kd <--**c**varies directly as d e =**k**/√f <-- e varies inversely as the square root of f. m = kn/...4 Answers · Science & Mathematics · 17/08/2019

... has detailed this approach. Each term is

**C**(n,**k**) * a^(n-**k**) * b^**k**a = x b = -4 Term 0:**C**(4,0) * x^4 * (-4)^0 -->...9 Answers · Science & Mathematics · 16/08/2019

... = pi*h*r^2 => dV/dt = pi*r^2 dh/dt or in this case 9*pi dh/dt. (

**c**) dV/dt =**k***h^(1/2) =>**k**= (-2) / sqrt(16) = -1/2. 9*pi dh/dt = (-1/2)*h^(1/2) => 18*pi...2 Answers · Science & Mathematics · 11/08/2019

...

**C**_atm is the atmospheric concentration, we would model this as: dC(t)/dt = -**k***(**C**(t) -**C**_atm) where**k**is some positive rate constant. Note that the...2 Answers · Science & Mathematics · 06/08/2019

(A) 20 = 200(1 - e^(-5k)) => 9/10 = e^(-5k) => ln(10/9) = 5k =>

**k**= 0.02107. (B) L = 200(1 - e^(-0.2107)) = 38. (**C**) 180 = 200(1 - e^(-0.02107 t)) => 1/10 = e^(-0.02107 t) => ln(10) = 0.02107 t => t = 109 minutes.1 Answers · Science & Mathematics · 28/07/2019

...and b subscript

**k**which might be part of your confusion. You want to show**c**(**k**) = 4c(**k**-1) 4c(**k**-1) = 4(2^(**k**-1) -1) = [2^(**k**+1)] - 4 (A) Now 2^(**k**...1 Answers · Science & Mathematics · 25/07/2019

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