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  1. F = k *Q1*Q2/d^2 = 9*10^9*3*7*10^-12*10^4/21^2 = 4.29 N 

    1 Answers · Science & Mathematics · 16/09/2020

  2. F = k e^2 / r^2 F = 9x10^9 * (1.602×10^−19)^2 / (1x10^−11)^2 F = 2.31 × 10^-6 N where e =  1.602×10^−19 C is charge od proton k = 9x10^9 N m^2/ C ^2 is Coulomb's constant

    1 Answers · Science & Mathematics · 17/09/2020

  3. ... - µ k *m₁*g m₂: m₂*a₂ = µ k *m₁*g ( c ) Zero for both, since there are no unbalanced forces. (d) for...

    2 Answers · Science & Mathematics · 17/09/2020

  4. ...or N/m, if you prefer; 19.74 before rounding) c . max U = ½kx² = ½*...2m)² = 39 J (using pre-rounded k value) d. max KE = 39 J = ½ * 2...

    1 Answers · Science & Mathematics · 12/09/2020

  5. the 3rd charge must be placed between the other two then must be: k q1 q3 / x13^2 = k q2 q3 / x23^2 or q1 / x13^2 = q2 / x23^2 then setting k ...

    1 Answers · Science & Mathematics · 17/09/2020

  6. ... / GmM where G = 6.674e−11 N·m²/kg² and k = 1/4πε₀ = 8.99e9 N·m²/C² and here q = -Q = 1.6e-19 C and m = 9.11e-31 kg and M = 1.67e-27kg Plugging in these values...

    2 Answers · Science & Mathematics · 17/09/2020

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