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F = k *Q1*Q2/d^2 = 9*10^9*3*7*10^-12*10^4/21^2 = 4.29 N

1 Answers · Science & Mathematics · 16/09/2020

F = k e^2 / r^2 F = 9x10^9 * (1.602×10^−19)^2 / (1x10^−11)^2 F = 2.31 × 10^-6 N where e = 1.602×10^−19 C is charge od proton k = 9x10^9 N m^2/ C ^2 is Coulomb's constant

1 Answers · Science & Mathematics · 17/09/2020

... - µ k *m₁*g m₂: m₂*a₂ = µ k *m₁*g ( c ) Zero for both, since there are no unbalanced forces. (d) for...

2 Answers · Science & Mathematics · 17/09/2020

...*ω*sin(kx - ωt) b. I = (p_max)² / 2ρv where p_max = B* k *A and ρ is the density of the liquid (see citation) c . Increase (obviously, and you'd hardly have to do the first two to...

1 Answers · Science & Mathematics · 20/09/2020

the 3rd charge must be placed between the other two then must be:

**k**q1 q3 / x13^2 =**k**q2 q3 / x23^2 or q1 / x13^2 = q2 / x23^2 then setting**k**...1 Answers · Science & Mathematics · 17/09/2020

... / GmM where G = 6.674e−11 N·m²/kg² and k = 1/4πε₀ = 8.99e9 N·m²/C² and here q = -Q = 1.6e-19 C and m = 9.11e-31 kg and M = 1.67e-27kg Plugging in these values...

2 Answers · Science & Mathematics · 17/09/2020

...theme: heat = mass * spec heat * temp change ΔQ = m* c *ΔT 7) ΔQ = 0.350kg * 128J... = 896 J since for CHANGES in temperature, 1 K = 1 ºC 8) ΔQ = 3kg * 4186J...

1 Answers · Science & Mathematics · 20/09/2020

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