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  1. (sin x + cos x)^2 = k sin x ^2 + cos x ^ 2 + 2*sin x * cos x = k (sin x ^2 + cos x ^ 2) + 2*sin x * cos x = k 1 + 2*sin x * cos x  = k 1 + sin 2x = k sin 2x = k - 1 let k - 1 = j find sin 2x = j where  0<...

    1 Answers · Science & Mathematics · 02/08/2020

  2. ...]^3 .. Q = ---- ---- ---- ---- ---  .. ... ... ... ..[CH4]^2 if Q > k , then the rxn is shifted to the left if Q < k ...

    2 Answers · Science & Mathematics · 08/08/2020

  3. ...g Height, h = (1/2) (8.5)² / (9.8) = 3.7 m (to 2 sig. fig.) ==== c . In part a, the answer depends on the total mass of the bike and the rider, as K .E. = (1/2) m v². In part b, the answer does not depend...

    1 Answers · Science & Mathematics · 06/08/2020

  4. your kind criticism is deeply appreciated, f u c k you very much 

    3 Answers · Entertainment & Music · 06/08/2020

  5. .../V .. .. . 00722 mol * 0.08206 Latm/molK * (273.15 + 26.9 K ) P = ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- = 3.52 atm...

    2 Answers · Science & Mathematics · 03/08/2020

  6. ... .. [At] = 0.280M .. [Ao] = 0.830M ... . t = ? .... k   = 0.270 / (M * s) you get to finish. 

    1 Answers · Science & Mathematics · 05/08/2020

  7. ...have been defined as 100 kPa and 273.15 K . By this definition, 1 mole of an ideal gas has...mol NH3 X 17.02 g/mol = 1.90 g NH3 c . 0.112 mol X 6.022X10^23 molecules...

    1 Answers · Science & Mathematics · 08/08/2020

  8. f(x) = (x^2-16)^6 Use derivative od composite function f'(x) = 6(x^2-16)^5 * 2x Equalize this to zero 6(x^2-16)^5 * 2x = 0 First solution is x=0 Other solutions are found from 6(x^2-16)^5=0 6((x+4)(x-4))^5 = 0 (x+4)^5 (x-4)^5 = 0 Two more...

    1 Answers · Science & Mathematics · 03/08/2020

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