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  1. First convert 0.47 atm = 47623 Pa. V = nRT/p = (2 mol)(8.3145 J/molK)(148 K)/(47623 Pa) = 0.0517 m^3 or 51.7 Liters.

    3 Answers · Science & Mathematics · 10/04/2019

  2. ... equation is used to solve this type of problem. F = k * q1 * q2 ÷ d^2 two positive charges of 6 x 10^-6 are separated...

    3 Answers · Science & Mathematics · 10/03/2019

  3. F[1,2] = F[2,3] -k * Q[1] * Q[2] / r[1,2]^2 = -k * Q[2] * Q[3] / r[2,3...

    2 Answers · Science & Mathematics · 11/08/2019

  4. ... vector arithmetic. for the left charge Ex = 2µk/r² pointed right Ey = 0 for the right charge... in Newtons/coulomb OR volts/meter k = 1/4πε₀ = 8.99e9 Nm²/C²

    1 Answers · Science & Mathematics · 27/08/2019

  5. ... is: τ₁ = rXT (cross product) = |i. . . . . j. . . . . k| |-Lsinθ Lcosθ 0| |T. . . . 0. . . . .0| = -LTcosθ k...

    2 Answers · Science & Mathematics · 23/06/2019

  6. Electrostatic force is F = k q^2 / r^2 then r = q (k / F)^1/2 where k = 9x10^9 Nm^2/C^2 [Coulomb constant] then r = 5.5x10^-8*(9x10^9 / 3.4)^1/2 = 2.83 mm

    1 Answers · Science & Mathematics · 30/04/2019

  7. (2πf)² = k/m = (2π*1.2)² = 56.85 = k/m m*56.85 = k = 0.3*56.85 = 17.055 F = kx = 1.1 = 17.055*x x = 1.1/17.055 = 6.5cm

    2 Answers · Science & Mathematics · 14/07/2019

  8. ... / A₂Y₂ for nylon ₁ + and copper ₂ 1m * 5e-5/K * -20K + 1m * 1.6e-5/K * -20K = F₁*1m / (π/4)(0.005m...

    1 Answers · Science & Mathematics · 21/09/2019

  9. potential = kQ / r where k = 1/4πε₀ = 8.99e9N·m²/C² so potential = 8.99e9N·m²...

    1 Answers · Science & Mathematics · 03/02/2020

  10. Δh = 5.90-1.35 = 4.55 m 31.9^2 = Vo^2+2*g*Δh Vo = √31.9^2-19.612*4.55 = 30.47 m/sec k*x^2 = m*Vo^2 k = m*Vo^2/x^2 = 0.035*30.47^2/0.111^2 ≅ 2640 N/m

    1 Answers · Science & Mathematics · 01/06/2019

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