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  1. 0.81 * cos 69 = 0.29 0.81 - 0.29 = 0.52 m release point above the bottom of the swing. PE = mgh = (1/2) m v^2, Kinetic energy gained as the pendulum swings down. a) v = sqrt [ 2gh] = sqrt [2 * 9.8 * 0.52] = 3.19 m/s b) the bob will swing to a height above the bottom of 0.52 m c) for half the speed at the bottom...

    1 Answers · Science & Mathematics · 16/07/2008

  2. a.) For simple harmonic motion: frequency = 0.98 amplitude (A) = 3.2 cm = 3.2 x 10^ -2 m angular frequency (w) = 2pi (frequency) = 6.15832 maximum velocity = Aw = (3.2 x 10^ -2)(6.15832) = 1.971 x 10^ -1 m/s b.) When the mass moves from y = 1.5 cm to y = 2.5 cm: y = 2.5 cm - 1.5 cm = 1.0 cm = 1 x 10^ -2 m...

    1 Answers · Science & Mathematics · 03/01/2010

  3. k = spring constant = 80 N/m m = mass = 0.5 kg L = distance from A to B = 2.5 m R = radius of...m)) E = 20.58 J That is the initial energy that must be stored in the spring. E = k×d²/2 (20.58 J) = (80 N/m)×d²/2 d = √[2×(20.58 J)/(80 N/m)] d = 0.7173 m

    1 Answers · Science & Mathematics · 25/01/2013

  4. K = (1/2) I omega^2 + (1/2) m v^2 , and omega = v/r I = (2/3) mr^2 => m = (3/2) I...20.32 m/s (1/2) mv^2 = (1/2)(0.276 kg)(20.32 m/s)^2 = about 50 J but use calculator. Looks like the K may be equally split among rotational and translational energies. (b) 20.32 m/s, from above (c) 95 J - (mg...

    1 Answers · Science & Mathematics · 27/11/2012

  5. The spring constant k = 720/(0.55*10^-3) = 1309*10^3 N/m Your energy at 1.3 m M... compressed, and the energy in the spring is E = 0.5*k*x^2, where x = compression 0.5*k*x^2 = 957.6 (x in meters) x = √[2*957...

    2 Answers · Science & Mathematics · 18/03/2008

  6. Step by step answers posted here http://www.mathskey.com/question2answer/1447/compute-%E2%88%87-x-a-for-a-vector ask your physics homework questions at http://www.mathskey.com/question2answer/… and get free math help. all the best

    1 Answers · Science & Mathematics · 19/02/2013

  7. 1.8k(omega) = 1,800 omega 1M omega = 1,000,000 omega

    1 Answers · Science & Mathematics · 16/06/2012

  8. Use the equation E = hc/lambda you will need to convert from eV to J (1eV = 1.6E-19J) The minimum voltage to be applied is 8.968 kV.

    2 Answers · Science & Mathematics · 13/12/2012

  9. k = F / x = 16lb / (8/9)ft = 18 lb·ft ω = √(k/m) = √(18lb·ft / (16lb / 32ft/s²)) = 6 rad/s So we can model...

    1 Answers · Science & Mathematics · 25/06/2016

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