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  1. I assume that you want to find the spring constant, k from hooks law. F = kx meaning that there is a linear relationship...

    1 Answers · Science & Mathematics · 31/10/2013

  2. 0 K > 0 F > 0 C 273 K = 0 C 32 F = 0 C 0 C = 0 C

    1 Answers · Science & Mathematics · 05/07/2011

  3. m = ku+v m = k{1,2,1} + {-2,3,2} m = {k-2, 2 k+3, k+2} vector m perpendicular to w if m • w = 0 {k-2, 2 k+3, k+2} • {4,-1,3} = 0 5 (k-1) = 0 k = 1

    2 Answers · Science & Mathematics · 28/09/2010

  4. ...2 = (kx^2)/2 here m is mass of the ball, v is the initial velocity, k is the spring constant and x is the value of compression=0.62 cm so put...

    2 Answers · Science & Mathematics · 14/06/2009

  5. Elastic Strain Energy = (1/2)kx^2 where k is the spring constant and x is the extension to work out the extension do...

    2 Answers · Science & Mathematics · 25/08/2013

  6. Is 10.5 the half life? For any half life the ratio of activity is 0.5 0.5 = e^(10.5k) ln(0.5) = 10.5k k=ln(0.5)/10.5

    1 Answers · Science & Mathematics · 12/12/2011

  7. ...ωcos(ωt + φ) x"(t) = -Aω²sin(ωt + φ) ω = √(k/m) ω = √(2/0.5) ω = 2 x'(0.1) = 0.263 = 2Acos(2(0.1...

    1 Answers · Science & Mathematics · 12/03/2014

  8. After k becomes to big, the force of streching the spring would break it. So yes, k could become too big depending on the material Assuming you meant the k in F=kx

    5 Answers · Science & Mathematics · 02/11/2007

  9. ...need detA = 0 which gives us: -63 + 7k^2 = 0. Hence k^2 = 9 or k = + or -3 (the only two such values.) Graphically ...

    1 Answers · Science & Mathematics · 03/05/2012

  10. The angular frequency ω = √k/m ω = 7.4 rad /s and k = 51N/m m= k /ω^2 = 51/7.7/7.4 = 0.9 kg. =============================

    2 Answers · Science & Mathematics · 07/07/2010

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