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The energy in the spring is 0.5*

**k***∆x^2; so E = 0.5***k***∆x^2 = 0.01 eV = 0.015*1.6*10^-19 J...1 Answers · Science & Mathematics · 06/04/2010

Hey, The leap in

**k**^2 comes from the fact that, for whatever model you're exploring, boundary...0, pi, 2pi, etc... For these conditions to be satisfied,**k**= n*pi/a for all values of n, which is where the extra terms...1 Answers · Science & Mathematics · 17/09/2009

Hooke's law just states: F = -

**k***x where F is the force**k**is the spring constant x is...0.0984m) = -**k***x1 =**k***(0.0984) Subtract the equations to eliminate**k***x1, and solve for**k**. Hope this helps2 Answers · Science & Mathematics · 01/12/2008

**k**is short for "kilo", and that is derived from a Greek word meaning "thousand"2 Answers · Science & Mathematics · 06/08/2011

(a) the frequency of the oscillation = (1/2pi)*sq rt(

**k**/m) = (1/2pi)*sq rt[186/4.2] = 1.059 or 1.06 Hz (b...change? Maximum kinetic energy = maximum potential energy = 0.5***k***(amplitude)^2 amplitude will be reduced by a factor of sq...3 Answers · Science & Mathematics · 25/11/2011

... / pf = 4.64 mol ∙ 8.3145 Pa∙m³∙

**K**⁻¹∙mol⁻¹ ∙ 343**K**/ 9.83×...7) => T' = T ∙ (pi/pf)^(2/7) = 343**K**∙ (2.01×10⁵ Pa / 9.83×10⁵ ...1 Answers · Science & Mathematics · 19/06/2012

A)

**k**= F/y = m*g/y = 0.3*9.8/.15 = 19.6 N/m B) A = 0.20 m C) w = √(**k**/m) = 8.083 rad/sec; Vmax = w*A = 1.616 m/s D) Θ...1 Answers · Science & Mathematics · 21/04/2013

Data: m = 0.20 kg,

**k**= 10 N/m, Maximum Amplitude => X = 0.080 m... given by the following formula:**K**.E = (1/2) (**k**) (X^2 - x^2) =>**K**.E = (0.5) (10) {(0.080)^2 - (0.040)^2...3 Answers · Science & Mathematics · 21/05/2012

**k**is a constant. usually re arranging the equation would help u to figure out**k**by using -F/x but use the net and find the spring constant of the object or material used.1 Answers · Science & Mathematics · 25/06/2011

**K**is kilo = 1000 mm is millimeters which is 1/1000 To convert from**K**to MM you multiply by 1,000,000 ie 1K = 10^6MM3 Answers · Science & Mathematics · 27/12/2010