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... vector arithmetic. for the left charge Ex = 2µ

**k**/r² pointed right Ey = 0 for the right charge... in Newtons/coulomb OR volts/meter**k**= 1/4πε₀ = 8.99e9 Nm²/C²1 Answers · Science & Mathematics · 27/08/2019

...standard temperature and pressure R = gas constant = 286 m²/s²/

**K**for air T = absolute temperature (273.15**K**+ °C) = 298.15**K**...3 Answers · Science & Mathematics · 24/08/2019

... = QE in Newtons/coulomb OR volts/meter

**k**= 1/4πε₀ = 8.99e9 Nm²/C² re the other problem, just use...2 Answers · Science & Mathematics · 23/08/2019

Potential energy of the spring at max compression is kx^2 / 2. This gets turned to gravitational potential energy at the top of the incline with no friction h = kx^2 / (2mg)

1 Answers · Science & Mathematics · 23/08/2019

... following equation is used to solve this problem. F =

**k*** Q1 * Q2 ÷ d^2 I use 9 * 10^9 for**k**. The unit of the...2 Answers · Science & Mathematics · 16/08/2019

You should post your answers so (if they are wrong) we can explain why they are wrong. 1a). Mass (m) stays the same. Volume (V) is halved. Since density = m/V, the density doubles. 1b) I don'...

1 Answers · Science & Mathematics · 18/08/2019

f = 1/(2 * π) * √(

**k**/m) The first step is solve problem 20 to determine the spring constant... to determine the increase of the length. ∆ L = 0.15 – 0.10 = 0.05 meter**k**= 4 ÷ 0.05 = 80 N/m Now we can use the spring constant to calculate the...2 Answers · Science & Mathematics · 16/08/2019

F[1,2] = F[2,3] -

**k*** Q[1] * Q[2] / r[1,2]^2 = -**k*** Q[2] * Q[3] / r[2,3...2 Answers · Science & Mathematics · 11/08/2019

1) E = 1/2

**k**A^2 E = 0.5 * 275 * 0.058^2 = 0.46 J 2) v = w A = sqrt(**k**/m) A v = sqrt(275/0.582) * 0.058 = 1.26 m/s 3) a = w^2 A = (**k**/m) A a = (275/0.582) * 0.058 = 27.41 m/s^22 Answers · Science & Mathematics · 08/08/2019

...data are given to 3 sig. figs, we should use the value of ‘

**k**’ to 3 sig. figs. E1 = kq1/d² = 8.99*10^9 * 6.60*10^-9...2 Answers · Science & Mathematics · 08/08/2019

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