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electrostatic force F = kQq / d² where

**k**= 8.99e9 N·m²/C² first condition: -0.119 N = 8....2 Answers · Science & Mathematics · 05/09/2019

...point to the left, and so the magnitude of the field at the midpoint is E =

**k***(q1 + q2) / (d/2)² E = 8.99e9N·m²/C² * (3.14e-...1 Answers · Science & Mathematics · 05/09/2019

energy =

**k***Q*q / d where**k**is some constant so adcb then dacb If you find this helpful, please award Best Answer!2 Answers · Science & Mathematics · 06/09/2019

...the proton must be placed below the q. Right! • F=m*g • [

**K**|q1||q2|]/r^2=m*g Yep. I'd write it as weight = electrostatic force...1 Answers · Science & Mathematics · 03/09/2019

The unrounded answer from part a) is 3.2344x10^17 N/C. It's best to use this unrounded value in part b). The force on charge q in field E is simply F = qE. We can ignore the electron charge's minus sign as we are only...

1 Answers · Science & Mathematics · 04/09/2019

... is force in newtons r is separation in meters

**k**= 8.99e9 Nm²/C²1 Answers · Science & Mathematics · 01/09/2019

...for both charges. Sum the horizontal components: Ex = (

**k***4e-6/18) * cos45 +**k***4e-6/18 *cos135 =**k***4e-6/18 *[0.7071-0.7071] = 0 Sum...1 Answers · Science & Mathematics · 01/09/2019

...the field due to the other two corner charges: kQ / (2L²) = 2*

**k***10nC*cos45º / L² which leads directly to Q...1 Answers · Science & Mathematics · 01/09/2019

...with q1 in place and then you bring in q2, the new potential energy is PE =

**k***q1*q2 / (0.200m*√2) and if you then bring in q3, you have PE' = PE...1 Answers · Science & Mathematics · 01/09/2019

... is force in newtons r is separation in meters

**k**= 8.99e9 Nm²/C²1 Answers · Science & Mathematics · 31/08/2019

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