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  1. ...m, 9.1 km pressure is about 30 kPa Temp is about 230 K density is about 0.46 kg/m³"{kg\m-3}" is meaningless...

    3 Answers · Science & Mathematics · 02/11/2019

  2. ...force = Static frictional force kx = μ(s)N kx = μ(s)mg x = μ(s)mg/k x = 0.60*1.5*9.8/(1.2 x 10³) x = 0.00735 m or 7.35 mm The block...

    2 Answers · Science & Mathematics · 20/10/2019

  3. L = Lo*(1+k*ΔT) L = 120*(1+17*10^-6*(24-21)) = 120.006 mm lenght increases by 6 μm

    1 Answers · Science & Mathematics · 20/10/2019

  4. tangential velocity Vt = ω*r = 23*1.75 m/sec Ke = m/2*V^2 = 18/2*(23*1.75)^2 = 14,581 joule or J = m*r^2 = 18*49/16 KE = J/2*ω^2 = 9*49/16*23^2 = 14,581 joule

    1 Answers · Science & Mathematics · 17/10/2019

  5. a. field E = σ / ε where ε = k*ε₀ so σ = Eε = 1.5e6N/C * 5*8.85e-12 C²...

    1 Answers · Science & Mathematics · 13/10/2019

  6. ...8200/18200)^2 this goes into the spring. 1/2 kx^2 = 1/2 m v^2 x^2 = m v^2 /k x = sqrt( m v^2 / k) = sqrt( 18200*(8.3 * 8200/18200)^2 / (3.2 * 10 ^ 5) ) = 0.89 m...

    2 Answers · Science & Mathematics · 11/10/2019

  7. ...dv/dx = -kx + 4.2 we want the point where dv/dx = 0, which is where x = 4.2 / k = 4.2 / 1100 = 0.0038 m = 0.38 cm ½mv² = 0.22 - ½...

    1 Answers · Science & Mathematics · 18/10/2019

  8. ... = 8.314 J/mol·K So you can compute the temperature change in K (which is the same as the temperature change in ºC, since for CHANGES...

    1 Answers · Science & Mathematics · 24/09/2019

  9. ...x / √(x²+y²) So, for Ey I get dEy = k*λ*dx*y / (x²+y²)^(3/2) so Ey = k*λ*y ∫ dx / (x²...

    3 Answers · Science & Mathematics · 23/09/2019

  10. ... / A₂Y₂ for nylon ₁ + and copper ₂ 1m * 5e-5/K * -20K + 1m * 1.6e-5/K * -20K = F₁*1m / (π/4)(0.005m...

    1 Answers · Science & Mathematics · 21/09/2019

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