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  1. ( 1/(y-k) - 1/y ) / k so i guess you want only one giant fraction, so lets clean up the.... you have to find a common denominator, which in this case is y(y-k). you multiply the first term in there by y/y and the second by (y-k...

    2 Answers · Education & Reference · 12/08/2010

  2. k=4 (x^3)^k is the same as (x^(3*k) therefore you cant set the equation: 3k=12 -> k=4

    3 Answers · Education & Reference · 23/11/2009

  3. ... correct vertex form is y = a (x - h)² + k. There is a way to find a, h, and k, but it... #1, using (2, 12): y = a (x - h)² + k 12 = a (2 - h)² + k 12 = a (4 - 4h + h²) + k...

    1 Answers · Education & Reference · 04/09/2009

  4. To find what K is, we have to use fractions. Since K is over... 32 by 11 to get 352, so your equation will now read: 440/11=k/11+352/11 When one part of an equation is a fraction, you need to make...

    5 Answers · Education & Reference · 04/10/2006

  5. k(x^2)-3x+2=0 When the discriminant of the quadratic formula is .... The discriminant is b^2 -4ac From the above equation, a = k, b = -3, and c = 2. Plugging in you get (-3)^2 - 4(k)(2) = 9 - 8k ...

    6 Answers · Education & Reference · 18/08/2007

  6. Get the k terms on one side of = and the non-k terms on the other d - vk = ck + m -m + vk..+ vk - m ---------------------------- d - m = ck + vk Factor out the k d - m = k(c + v) Divide by (c + v) (d - m) / (c + v) = k

    1 Answers · Education & Reference · 11/09/2010

  7. x^2 + (k-1)x = 2k+1 This is a quadratic equation of the form ax^2+bx+c=0...it will have no real solutions. The equation above is x^2 + (k-1)x - (2k+1) = 0 where a=1, b=k-1, and c= -(2k+1) To get 2 real ...

    1 Answers · Education & Reference · 23/02/2008

  8. k-8/7+k = -1/5 okay :P afraid? maths <3 awesome :P love XD 5(k-8) = -1 (7+k) 5k - 40 = -7 - k 5k+k= -7 + 40 6k = 33 k= 33/6

    2 Answers · Education & Reference · 07/10/2012

  9. K = 1/2 a b sin(c) The mathematics for this go back to the Greeks...to Hero (or Heron) of Alexandria (c. 10–70 AD). K is just an arbitrary letter, possibly simply chosen to not be confused...

    1 Answers · Education & Reference · 07/05/2010

  10. (k+5)^2 -12k(k+2) (k+5)(k+5)-12k(k+2) k^2+10k+25-12k(k+2) k^2+10k+25-12k^2-24k -11k^2+10k+25-24k -11k^2-14k+25 is the answer

    5 Answers · Education & Reference · 08/11/2009

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