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( 1/(y-

**k**) - 1/y ) /**k**so i guess you want only one giant fraction, so lets clean up the.... you have to find a common denominator, which in this case is y(y-**k**). you multiply the first term in there by y/y and the second by (y-**k**...2 Answers · Education & Reference · 12/08/2010

**k**=4 (x^3)^**k**is the same as (x^(3***k**) therefore you cant set the equation: 3k=12 ->**k**=43 Answers · Education & Reference · 23/11/2009

... correct vertex form is y = a (x - h)² +

**k**. There is a way to find a, h, and**k**, but it... #1, using (2, 12): y = a (x - h)² +**k**12 = a (2 - h)² +**k**12 = a (4 - 4h + h²) +**k**...1 Answers · Education & Reference · 04/09/2009

To find what

**K**is, we have to use fractions. Since**K**is over... 32 by 11 to get 352, so your equation will now read: 440/11=**k**/11+352/11 When one part of an equation is a fraction, you need to make...5 Answers · Education & Reference · 04/10/2006

**k**(x^2)-3x+2=0 When the discriminant of the quadratic formula is .... The discriminant is b^2 -4ac From the above equation, a =**k**, b = -3, and c = 2. Plugging in you get (-3)^2 - 4(**k**)(2) = 9 - 8k ...6 Answers · Education & Reference · 18/08/2007

Get the

**k**terms on one side of = and the non-**k**terms on the other d - vk = ck + m -m + vk..+ vk - m ---------------------------- d - m = ck + vk Factor out the**k**d - m =**k**(c + v) Divide by (c + v) (d - m) / (c + v) =**k**1 Answers · Education & Reference · 11/09/2010

x^2 + (

**k**-1)x = 2k+1 This is a quadratic equation of the form ax^2+bx+c=0...it will have no real solutions. The equation above is x^2 + (**k**-1)x - (2k+1) = 0 where a=1, b=**k**-1, and c= -(2k+1) To get 2 real ...1 Answers · Education & Reference · 23/02/2008

**k**-8/7+**k**= -1/5 okay :P afraid? maths <3 awesome :P love XD 5(**k**-8) = -1 (7+**k**) 5k - 40 = -7 -**k**5k+**k**= -7 + 40 6k = 33**k**= 33/62 Answers · Education & Reference · 07/10/2012

**K**= 1/2 a b sin(c) The mathematics for this go back to the Greeks...to Hero (or Heron) of Alexandria (c. 10–70 AD).**K**is just an arbitrary letter, possibly simply chosen to not be confused...1 Answers · Education & Reference · 07/05/2010

(

**k**+5)^2 -12k(**k**+2) (**k**+5)(**k**+5)-12k(**k**+2)**k**^2+10k+25-12k(**k**+2)**k**^2+10k+25-12k^2-24k -11k^2+10k+25-24k -11k^2-14k+25 is the answer5 Answers · Education & Reference · 08/11/2009

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