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**k**- 1 - 12/(**k**- 1) = 1 Multiply both sides by**k**- 1 to get..**k**(**k**- 1) -**k**+ 1 - 12 =**k**- 1**k**² -**k**-**k**- 11 =**k**- 1**k**² - 2**k**- 11 =**k**- 1 Bring...4 Answers · Science & Mathematics · 28/08/2011

Definitely the

**K**Blade Tour, even though my instructor ...an ease for you to wrist snap on your serves.**K**Pro is also very head light but its ...3 Answers · Sports · 07/12/2008

You could solve

**k**^2 - 3k + 5 = 0 and plug the two solutions into the second expression... for**k**. You can, however, use the original equation to simplify the**k**^4 expression:**k**^4 - 6k^3 + 9k^2 - 7**k**^2(**k**^2 - 6k + 9) - 7**k**^2(**k**^2 - 3k - 3k...4 Answers · Science & Mathematics · 26/11/2008

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**k*** (lnx)^n dx is wor**k**ed out by parts u = (lnx)^n, and dv/dx = x^**k**then du/dx = (n/x)* (lnx)^n-1 , v = x^(**k**+1 /**k**+1 so S(**k**,n) = (lnx...2 Answers · Science & Mathematics · 07/06/2007

If

**k**is not divisible by 4 or 6, then both cos (**k**π/4) and cos (**k**π/6) will have magnitude less than 1 and so their...exist (the sequence is -2, 0, -2, 0, ....). If**k**is divisible by 24, both angles will be...1 Answers · Science & Mathematics · 31/03/2008

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**k**- 1)x² - (**k**+ 1)x + 2 = 0 first off, notice that**k**<> 1 because... linear and can have only 1 solution now, proceed as you did until: (**k**- 3)² > 0**k**> 0 ← this step is not justified...1 Answers · Science & Mathematics · 02/04/2011

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**k**s". Anyway... = = = = = = = = = = = = = = = = = = y = x² + (**k**+ 2)x + 2**k**+ 1 If the curve touch the x-axis, then y must be nil: y = 0 ...3 Answers · Science & Mathematics · 17/09/2013

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**k**< -4 (a) Multiply all three parts by -1. ...the inequalities: 5 > -**k**> 4 or equivalently 4 < -**k**< 5 -**k**is between 4 and 5. (b) Add 5 to all three...1 Answers · Science & Mathematics · 27/12/2013

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**k**)= (1/a) +(1/b) +(1/c) Multiply both abc →abc(1/**k**)=abc{(1/a) +(1/b) +(1/c)} →abc(1/**k**)=bc +ac +ab Divide both sides...3 Answers · Science & Mathematics · 15/08/2012

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