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Meanings for K * In accounting and investment banking, K = 1000 (similar... between May 16 and 31 of a year. o in infrared astronomy, the K-band is the region around 2.2 µm wavelength. * In baseball, K...
11 Answers · Business & Finance · 13/12/2006
The earliest example of O.K. that he unearthed (and it is so far still the...would have the 'contribution box,' et ceteras, o.k. -- all correct -- and cause the corks to fly, like ...
4 Answers · Education & Reference · 06/10/2007
-k^3 + k^2 + 2*k + 4 = -k(k^2 -k - 2) + 4 = -k(k^2 -2k + k -2) + 4 = -k[k(k-2) + 1(k-2)] + 4 = -k(k+1)(k-2) + 4 How do you want us to calculate? What...
1 Answers · Education & Reference · 25/01/2011
(h, k) Explanation: y = a*(x – h)^2 + k If x = h, then y = a*(h – h)^2 + k y = a*(0)^2 + k...a > 0 i.e. the parabola has upward orientation, then a + k > k. Therefore, y = k is the lowest...
3 Answers · Science & Mathematics · 08/06/2011
k^2 - 3k = 28 k^2 - 3k - 28 = 0 (k - 7)(k + 4) = 0 k = -4, 7 and if you're asked to find x: k = -4: -4 = (x + 3)/(x - 4) -4(x - 4) = x + 3 -4x + 16 = x + 3 16 - 3 = x...
2 Answers · Science & Mathematics · 18/08/2019
(i+1)^k = -(3^k) => ((1+i)/3)^k = -1 => ln[((1+i)/3)^k] = ln(-1) => k ln((1+i)/3) = ln(-1) => k [ (1/2...k/2) and the abs. v. of the right side is 3^k, and a power of 3 cannot be equal to a power of...
2 Answers · Science & Mathematics · 06/05/2013
Assume |k−√2| < ϵ. Need to prove that | (k+2)/(k+1)−√2... from |k−√2| < ϵ assemble an expression for (k+2)/(k+1)−√2 |k−√2| < ϵ → √2−ϵ &...
1 Answers · Science & Mathematics · 28/02/2013
Suppose K is not compact. Then, by Heine Borel theorem, K...since K is unbounded, for every M > 0 there is x ∈ K such that f(x) = ||x|| > M, which shows f is a continuous unbounded...
2 Answers · Science & Mathematics · 04/07/2010
PV = k means the process is being carried out so slowly that (take...on P-V diagram the product of P and V will remain constant k , which will be determined by that T which is desirably ...
1 Answers · Science & Mathematics · 06/04/2007
y = 2x + k ← this is a line y = x² + kx + 5 ← this is a curve y = y → 2 points → 2 solutions for x x² + kx + 5 = 2x + k x² + kx + 5 - 2x - k = 0 x² + x.(k - 2) + (5 - k) = 0 Polynomial...
3 Answers · Science & Mathematics · 22/01/2016