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  1. ...revolution is 16 s and the period is 32 s let's try h = 9 sin (ω(t+k)) + 7 the 9 is because the diameter is 18, radius is 9. The...

    1 Answers · Science & Mathematics · 18/06/2019

  2. ...exclusive, so 22 + 23 + 25 + 26 + 27 + 29 + ... + 123 + 125 [j = 22 to 125] ∑(j) - 4 × [k = ⌈22/4⌉ to ⌊125/4⌋] ∑(k) *** = ([j = 1 to 125] ∑(j) - [j = 1 to 21] ∑(j)) - 4...

    3 Answers · Science & Mathematics · 29/06/2019

  3. when n ≥ 5 then 25 ≤ n²... and w & k must come from the manner you write the bounds ..... O(n²) ≈ k...

    1 Answers · Science & Mathematics · 09/06/2019

  4. ...must be scalar multiples of each other. That is we must have, (k +1, 3k + 1, k - 3) = λ(-3, -10, -5) Setting each component equal to each other...

    2 Answers · Science & Mathematics · 04/06/2019

  5. h(2) = k (gf)(2) = k g(2) * f(2) = k -4 * -3 = k k = 12

    1 Answers · Science & Mathematics · 22/05/2019

  6. ...5321 is a factor of m². Therefore, there is some integer k such that m² = 5321k = 5321n². Therefore, we may write ...

    2 Answers · Science & Mathematics · 20/05/2019

  7. ...)((C(x) ^ O(x)) => ((Ey)(O(y) ^ H(y) ^ K(x,y)))). #2. (a) (F(a,a) v F(a,b) v F(a,c)) ^ (F(b...

    1 Answers · Science & Mathematics · 20/05/2019

  8. period = k/2 period = 2pi/B = k/2 ... solve for B B = 2/k X 2pi = 4pi/k A. is correct

    2 Answers · Science & Mathematics · 13/05/2019

  9. ...(2θ) dy/dx = tan(2θ) For horizontal tangents tan(2θ) = 0 2θ = kπ θ = kπ/2 θ = 0 and π/2 Points are (0,0) and(a,π/2) ...

    2 Answers · Science & Mathematics · 06/05/2019

  10. 2.31 = 0.54 x (k^44) k = ~1.0336 C(2000) = 0.54 x (1.0336^56) = $3.44 C(2010) = 0.54 x (1.0336^66) = $4.78

    2 Answers · Science & Mathematics · 30/04/2019

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