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1. ### If a 20 kg of mass, m, is attached to the above spring in problem 20 (spring constant k), what will the frequency of oscillation, f, be?

f = 1/(2 * π) * √(k/m) The first step is solve problem 20 to determine the spring constant... to determine the increase of the length. ∆ L = 0.15 – 0.10 = 0.05 meter k = 4 ÷ 0.05 = 80 N/m Now we can use the spring constant to calculate the...

2 Answers · Science & Mathematics · 16/08/2019

2. ### Attach an object A of mass m to the left end of the spring with a spring constant k and an object B of 2m to the right end as shown?

...2 ] + 0.5k[y(t) - x(t) - a]^2 = 0.5m(v_0)^2 (v_0)^2 - (dx/dt)^2 - 2(dy/dt)^2 = (k/m)[y(t) - x(t) - a]^2 4. When dx/dt = 0 then dy/dt = v_0 / 2 Plug...

1 Answers · Science & Mathematics · 28/06/2019

3. ### .210 moles of a diatomic gas are in a piston the gas dos 185J of work while 390 of heat are added what is the change in temperature?

For diatomic ideal gas U = 5/2 nRT (should be Delta on U and T) U = Q - W T = (Q-W)/(5/2 nR) = (390-185)/(5/2 0.21*3.814)

1 Answers · Science & Mathematics · 23/05/2019

4. ### What is the resultant pressure if 0.7 mol ofideal gas at 273 K and 2.37 atm in a closedcontainer of constant volume is heated?

Let’s use the following equation to determine the final pressure of the gas. P1 ÷ T1 = P2 ÷ T2 2.37 ÷ 273 = P2 ÷ 610 P2 * 273 = 1,445.7 P2 =1,445.7 ÷ 273 This is approximately 5.3 atm. I hope this is helpful for you.

2 Answers · Science & Mathematics · 12/05/2019

5. ### The mechanical equivalent of heat is 1 cal = 4.18 J. The specific heat of water is 1 cal/g · K.?

A 20° C change is also a 20° K change.

2 Answers · Science & Mathematics · 09/01/2019

6. ### a m=1.50 kg block attached to a massless spring (k=1400N/m). The block is pulled to a position 5.00 cm to the left of its equilibrium?

... energy is conserved PE max = PE at 2cm + KE at 2cm 1/2(1400)(0.0500^2) = 1/2(1400)(0.0200^2) + 1/2 (1.50) v^2 1/2 's cancel 3.5 = 0.56 + 1.50 v^2 1.50 ^2 = 2.94 v^2 = 1.96 v = 1.4 m/s When you get a good response, please consider giving a best answer. This...

1 Answers · Science & Mathematics · 17/04/2019

7. ### Two 4.4 μF capacitors, two 2.5 kΩ resistors, and a 11.4 V source are connected in series.?

two 4.4 in series are equal to 2.2 two 2.5k in series are equal to 5 time constant = 2.2µ x 5k = 11 ms voltage across 5k is 1.5•5 = 7.5 volts voltage across cap = 11.4–7.5 = 3.9 volts v = v₀[1–e^(–t/τ)] 3.9 = 11.4[1–e^(–t/11m)] 1–e^(–t/11m) = 0.3421 e^(–t/11m) = 0.6579 –t/11m...

1 Answers · Science & Mathematics · 02/05/2019

8. ### a spring with k=33.5 n/m has 1.2kg mass attached it is pulled .12m and released how much mechanical energy does it have?

Assuming the system has no friction, it's a simple harmonic oscillator and therefore has constant mechanical energy. When the spring is fully stretched, all of that mechanical energy is spring potential E = PS E = ½kA²...

2 Answers · Science & Mathematics · 28/05/2019

9. ### a .15kg is attached to a spring with k=18.9 n/m at the equilibrium position it moves 2.39 m/s how mechanical energy does it have?

At equilibrium position, there is no spring potential energy. E = 0.5mv^2 = 0.5*0.15*2.39^2 = 0.428 J

2 Answers · Science & Mathematics · 28/05/2019

10. ### A child decides to use his toy gun to launch a 3 gram pebble vertically into the air. If the spring inside (k= 600 N/m) is compressed...?

During the time that the pebble is being launched, there are two forces on the pebble. The force exerted by the toy gun is the upward force. Its weight is the downward force. Let’s determine the work that is done...

2 Answers · Science & Mathematics · 28/01/2019