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  1. f = 1/(2 * π) * √(k/m) The first step is solve problem 20 to determine the spring constant... to determine the increase of the length. ∆ L = 0.15 – 0.10 = 0.05 meter k = 4 ÷ 0.05 = 80 N/m Now we can use the spring constant to calculate the...

    2 Answers · Science & Mathematics · 16/08/2019

  2. 1) E = 1/2 k A^2 E = 0.5 * 275 * 0.058^2 = 0.46 J 2) v = w A = sqrt(k/m) A v = sqrt(275/0.582) * 0.058 = 1.26 m/s 3) a = w^2 A = (k/m) A a = (275/0.582) * 0.058 = 27.41 m/s^2

    2 Answers · Science & Mathematics · 08/08/2019

  3. F[1,2] = F[2,3] -k * Q[1] * Q[2] / r[1,2]^2 = -k * Q[2] * Q[3] / r[2,3...

    2 Answers · Science & Mathematics · 11/08/2019

  4. l = 10cm = 0.1 m k = 0.84 J/s·m·C A = 30 m² ΔT = 360 ...

    2 Answers · Science & Mathematics · 15/08/2019

  5. EDIT. The force on each charge is: F = k.q1.q2/r² = 9x10^9 x 11.5x10^-6 x (-7.55)x10^-6 / 2.95² = -0.0898...

    3 Answers · Science & Mathematics · 07/08/2019

  6. ... following equation is used to solve this problem. F = k * Q1 * Q2 ÷ d^2 I use 9 * 10^9 for k. The unit of the...

    2 Answers · Science & Mathematics · 16/08/2019

  7. ... it as a constant is very small. So use 4.2 * 10 ^ 3 J/kg/K Energy = dT * m * specific heat = 41 * 55.5 * 4.2 * 10 ^ 3 no of kw...

    2 Answers · Science & Mathematics · 03/08/2019

  8. ...between them and cancel where they have equal magnitude. We can factor out k and 1e-6 and write: 1.6/r² = 3.1/(0.15-r)² 1.6(0.15-r)²...

    3 Answers · Science & Mathematics · 07/08/2019

  9. The sum of forces F = W (sin(theta) - k cos(theta)) - P = 0 when not sliding. So P = 300*(sin(radians(45)) - .3*cos(radians(45))) = 148.5 lbs. ANS.

    2 Answers · Science & Mathematics · 25/07/2019

  10. ...data are given to 3 sig. figs, we should use the value of ‘k’ to 3 sig. figs. E1 = kq1/d² = 8.99*10^9 * 6.60*10^-9...

    2 Answers · Science & Mathematics · 08/08/2019

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