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  1. Note that Σ(k = 5 to ∞) C(k-1, k-5) k^3/2^k...to ∞) (k-1)(k-2)(k-3)(k-4) * k^3 x^k {at x = 1/2} = (1/24) x^5 * Σ(k...%29+C%28k-1%2C+k-5%29+k^3%2F2^k I hope...

    1 Answers · Science & Mathematics · 29/07/2014

  2. 0=< k =<4 points of intersection are (-1,1) and (-3,1...solve it with 2 quadratic equations, one for each point. You will get k. For (-1,1), k is between (0,2) For (-3,1), k is...

    2 Answers · Science & Mathematics · 02/09/2008

  3. 2kx² - 12x + (k+7) = 0 Solve for k b² - 4ac = 0 (b = -12, a = 2k and c = k...8 ..........-k² - 7k + 18 = 0 .......... k² + 7k - 18 = 0 ........ (k - 2) (k + 9) = 0 ......k - 2 = 0.......................... k + 9 = 0 k - 2 + 2 = 0 + 2...

    4 Answers · Science & Mathematics · 12/09/2010

  4. Hello, x³ – (k + 1)x + 2k = 0 = = = = = = = = = = = = = = = = = = = = = = Obviously, if k=0, we obtain... prime and k≠0: Then 2k has four divisors: 1, 2, k and 2k. Rational root theorem induce that if a rational root exists...

    2 Answers · Science & Mathematics · 10/12/2012

  5. Goal: To get "k" isolated by itself. a.) 0 = 14 + k In order to isolate... so that the 3.3 on the variable side will turn into 0 and will not count. -0.8 = k + 3.3 -0.8 - 3.3 = k + 3.3 - 3.3 -4.1 = k + 0 Since the zero does...

    3 Answers · Science & Mathematics · 16/06/2011

  6. a(n) = Σ(k = 0 to ∞) 10^(-k^2) is irrational (choice C, assuming you mean...bit more, showing that it is transcendental. Let p(n) = Σ(k = 0 to n) 10^(n - k^2) and q(n) = 10^n. Then, |Σ(k = 0 to ∞) 10...

    2 Answers · Science & Mathematics · 13/04/2013

  7. (k - 2)x^2 + (k - 5)x - 5 = 0 The roots are equal if the discriminant... discriminant, b^2 - 4ac, evaluated as follows: (k - 5)^2 - 4(k - 2)(-5) And we want this to be equal to zero. (k...

    3 Answers · Science & Mathematics · 06/12/2008

  8. Let k ≥ 2. Then p_(k - 1) + 3k - 2 = (k - 1)[3(k - 1) - 1]/2 + (6k - 4)/2 = [(k - 1)(3k - 3 - 1) + 6k - 4]/2 = [(k - 1)(3k - 4) + 6k - 4]/2 = (3k² - 7k...

    1 Answers · Science & Mathematics · 13/09/2009

  9. k * 3^k = 1,000,000,000 Start by taking the natural logarithm of both sides of the equation to remove that variable from the exponent:*** ln(3^k)(k) = ln(1,000,000,000) Now the exponent of a factor here can be ...

    1 Answers · Science & Mathematics · 21/09/2008

  10. k(k - 5) > 0 in two cases: 1) k > 0 and (k - 5) > 0 2) k < 0 and (k - 5) < 0 In case 1, k > 0 and k > 5; both of these are true when k > 5. In case 2, k...

    1 Answers · Science & Mathematics · 11/04/2010

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