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  1. k^0.5 = 6 square the whole equation (k^0.5 = 6)^2 k = 6^2 k= 36 RainMaker nifty-rainmaker.blogspot.com/

    5 Answers · Science & Mathematics · 10/05/2010

  2. (k + 2)/3 = k/2 - 2 k + 2 = 3/2*k - 6 2 = 1/2*k - 6 8 = 1/2*k k = 16

    3 Answers · Science & Mathematics · 02/03/2009

  3. Let (x - k) / (x - 1) = y x - k = yx - y x = yx - y + k x - yx = y + k x(1 - y) = y + k x = (-y + k) / (1 - y) x = (y - k) / (y - 1) It would seem that the function is generally its own inverse...

    2 Answers · Science & Mathematics · 12/08/2010

  4. f(x) = k - x² ← this is the curve y = 4x - 9 ← this is the line ... us only one point, so only one solution to the equation 4x - 9 = k - x² x² + 4x - 9 - k = 0 x² + 4x - (9 + k) = 0 ...

    4 Answers · Science & Mathematics · 24/09/2015

  5. You can't. You have to know what k is. That said, if you have other conditions which...like: (3x + m)(x + n) where m and n are integers, and: mn = k m + 3n = 16 ==> m = 16 - 3n k = n(16 - 3n) = 16n - 3n² So, pick...

    2 Answers · Science & Mathematics · 01/08/2008

  6. If k-2 divides 2k, k-2 ≠ 0, then there is an integer i such that 2k = (k-2)i Solving for k gives... of i less than or equal to 1 that produce k≥ 3. Therefore the only ...

    1 Answers · Science & Mathematics · 20/03/2009

  7. Let K be a convex subset of R^p and let x,y be in the closure of K. Then there exist sequences (x_n), (y_n) of points in K such that lim x_n = x and lim y_n = y. The line segment between x_n and y_n...

    2 Answers · Science & Mathematics · 20/01/2012

  8. ∫(x = 0 to 1) x^k ln x dx = ∫(∞ to 0) (e^w)^k * w * (e^w...;==> x = e^w = -∫(w = 0 to ∞) we^((k+1)w) dw = -∫(w = 0 to ∞) we^((k+1)w) dw...1)t))] = (-1/(k+1)^2) * [1 + lim(t→∞) -e^((k+1)t)] = (-1/(k+1)^2) * (1 + 0), since k+1...

    3 Answers · Science & Mathematics · 10/06/2015

  9. x - k(x² - 3x + 2) = 0 x - kx² + 3kx - 2k = 0 -kx² + 3kx + x - 2k...discriminant must be greater than or equal to zero discriminant: b² - 4ac a = k b = -3k - 1 c = 2k b² - 4ac ≥ 0 (-3k - 1)² - 4(k)(2k) ≥ 0...

    1 Answers · Science & Mathematics · 28/04/2008

  10. k(k+1)(2k+1)/6 must be divisible by 100 means k(k+1)(2k+1) divisible by 600 which is 5x5x2x2x2x3 2k+1 is odd, and only one of k or k+1 can be even so you need k or k+1 divisible by 8 one of k, k+1, and 2k+1 will always be divisible...

    4 Answers · Science & Mathematics · 18/12/2013

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