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**k**^0.5 = 6 square the whole equation (**k**^0.5 = 6)^2**k**= 6^2**k**= 36 RainMaker nifty-rainmaker.blogspot.com/5 Answers · Science & Mathematics · 10/05/2010

(

**k**+ 2)/3 =**k**/2 - 2**k**+ 2 = 3/2***k**- 6 2 = 1/2***k**- 6 8 = 1/2***k****k**= 163 Answers · Science & Mathematics · 02/03/2009

Let (x -

**k**) / (x - 1) = y x -**k**= yx - y x = yx - y +**k**x - yx = y +**k**x(1 - y) = y +**k**x = (-y +**k**) / (1 - y) x = (y -**k**) / (y - 1) It would seem that the function is generally its own inverse...2 Answers · Science & Mathematics · 12/08/2010

f(x) =

**k**- x² ← this is the curve y = 4x - 9 ← this is the line ... us only one point, so only one solution to the equation 4x - 9 =**k**- x² x² + 4x - 9 -**k**= 0 x² + 4x - (9 +**k**) = 0 ...4 Answers · Science & Mathematics · 24/09/2015

You can't. You have to know what

**k**is. That said, if you have other conditions which...like: (3x + m)(x + n) where m and n are integers, and: mn =**k**m + 3n = 16 ==> m = 16 - 3n**k**= n(16 - 3n) = 16n - 3n² So, pick...2 Answers · Science & Mathematics · 01/08/2008

If

**k**-2 divides 2k,**k**-2 ≠ 0, then there is an integer i such that 2k = (**k**-2)i Solving for**k**gives... of i less than or equal to 1 that produce**k**≥ 3. Therefore the only ...1 Answers · Science & Mathematics · 20/03/2009

Let

**K**be a convex subset of R^p and let x,y be in the closure of**K**. Then there exist sequences (x_n), (y_n) of points in**K**such that lim x_n = x and lim y_n = y. The line segment between x_n and y_n...2 Answers · Science & Mathematics · 20/01/2012

∫(x = 0 to 1) x^

**k**ln x dx = ∫(∞ to 0) (e^w)^**k*** w * (e^w...;==> x = e^w = -∫(w = 0 to ∞) we^((**k**+1)w) dw = -∫(w = 0 to ∞) we^((**k**+1)w) dw...1)t))] = (-1/(**k**+1)^2) * [1 + lim(t→∞) -e^((**k**+1)t)] = (-1/(**k**+1)^2) * (1 + 0), since**k**+1...3 Answers · Science & Mathematics · 10/06/2015

x -

**k**(x² - 3x + 2) = 0 x - kx² + 3kx - 2k = 0 -kx² + 3kx + x - 2k...discriminant must be greater than or equal to zero discriminant: b² - 4ac a =**k**b = -3k - 1 c = 2k b² - 4ac ≥ 0 (-3k - 1)² - 4(**k**)(2k) ≥ 0...1 Answers · Science & Mathematics · 28/04/2008

**k**(**k**+1)(2k+1)/6 must be divisible by 100 means**k**(**k**+1)(2k+1) divisible by 600 which is 5x5x2x2x2x3 2k+1 is odd, and only one of**k**or**k**+1 can be even so you need**k**or**k**+1 divisible by 8 one of**k**,**k**+1, and 2k+1 will always be divisible...4 Answers · Science & Mathematics · 18/12/2013