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a[

**k**] = 1/ln(**k**)^ln(**k**) a[**k**+1] = 1/ln(**k**(1+1/**k**))^ln(**k**+1) = 1/( ln(**k**) + ln(1+1/**k**))^ln(**k**+1) = 1/ ( ln(**k**)^ln(**k**+1) ( 1+ (ln(1+1/**k**)/ln(**k**) )^ln(**k**+1) a[**k**]/a[**k**+1] =ln(**k**)(1+(ln...3 Answers · Science & Mathematics · 18/04/2007

"

**k**multiplied by three": 3k "the sum of**k**multiplied by three and**k**": 3k +**k**"the sum of**k**multiplied by three and**k**is 12": 3k +**k**= 12 3k +**k**= 12 4k = 12**k**= 12/4**k**= 32 Answers · Science & Mathematics · 22/04/2012

========= x^2 +

**k**+ 6 = kx +3x x^2 -x(**k**+3) + (**k**+6) = 0 The equation will have equal ... happens when the discriminant is zero. So, solve (**k**+3)^2 - 4(**k**+6) = 0**k**^2 + 6k + 9 - 4k - 24 = 0**k**^2 + 2k - 15 = 0 (**k**+5)(**k**-3...2 Answers · Science & Mathematics · 14/10/2012

y = 2x +

**k**← this is a line y = x² + kx + 5 ← this is a curve y = y → 2 points → 2 solutions for x x² + kx + 5 = 2x +**k**x² + kx + 5 - 2x -**k**= 0 x² + x.(**k**- 2) + (5 -**k**) = 0 Polynomial...3 Answers · Science & Mathematics · 22/01/2016

... D between two points = sqrt[(x-x1)^2 +(y-y1)^2] D = sqrt[(

**k**+3)^2 +(**k**-0)^2] = sqrt[(**k**-0)^2 +(**k**-6)^2] sqrt[(**k**+3)^2 +(**k**-0)^2] = sqrt[(**k**-0)^2...4 Answers · Science & Mathematics · 12/09/2010

**k**^0.5 = 6 square the whole equation (**k**^0.5 = 6)^2**k**= 6^2**k**= 36 RainMaker nifty-rainmaker.blogspot.com/5 Answers · Science & Mathematics · 10/05/2010

(

**k**+ 2)/3 =**k**/2 - 2**k**+ 2 = 3/2***k**- 6 2 = 1/2***k**- 6 8 = 1/2***k****k**= 163 Answers · Science & Mathematics · 02/03/2009

Let (x -

**k**) / (x - 1) = y x -**k**= yx - y x = yx - y +**k**x - yx = y +**k**x(1 - y) = y +**k**x = (-y +**k**) / (1 - y) x = (y -**k**) / (y - 1) It would seem that the function is generally its own inverse...2 Answers · Science & Mathematics · 12/08/2010

f(x) =

**k**- x² ← this is the curve y = 4x - 9 ← this is the line ... us only one point, so only one solution to the equation 4x - 9 =**k**- x² x² + 4x - 9 -**k**= 0 x² + 4x - (9 +**k**) = 0 ...4 Answers · Science & Mathematics · 24/09/2015

You can't. You have to know what

**k**is. That said, if you have other conditions which...like: (3x + m)(x + n) where m and n are integers, and: mn =**k**m + 3n = 16 ==> m = 16 - 3n**k**= n(16 - 3n) = 16n - 3n² So, pick...2 Answers · Science & Mathematics · 01/08/2008

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