Let n be odd so n = 2h+1 where h is an integer then n^2 = 4h^2 + 4h + 1 = 4h(h+1) + 1 Of h and (h+1) one has to be even since they are consecutive integers; it follows that h(h+1) = 2k So n^2 = 8k+1
3 Answers · Science & Mathematics · 02/08/2019
...notation is different (y, Y and n used rather than x and X and k respectively).
1 Answers · Science & Mathematics · 30/07/2019
The given series is ∑[k = 0,∞] 5(-2z)ᵏ. initial term = 5 common ratio = -2z If the series ...
3 Answers · Science & Mathematics · 27/07/2019
... all of the rates that you have, gives you some number k. This number is also equivalent to some other rate that is...
2 Answers · Science & Mathematics · 26/07/2019
...notation as c(i) = the i-th term. You have things like c0 and b subscript k which might be part of your confusion. You want to show c(k) = 4c(k-1...
1 Answers · Science & Mathematics · 25/07/2019
- related to K