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  1. ...3 , 12) Plug this into the point-slope form for a line and solve for y. y - k = m * (x - h) y - 12 = 7 * (x - 3) y - 12 = 7x - 21 y = 7x - 9

    7 Answers · Science & Mathematics · 15/09/2019

  2. ... second one switches to counting tails (n = 5, k = 2, p = 1/3, q = 2/3). The third wants *at least* 3 ...

    1 Answers · Science & Mathematics · 14/09/2019

  3. ... the cos(x) = 5 result since |cos(x)| ≤ 1 cos(x) = 1/2 x = ±π/3 ± 2kπ for 0 ≤ x < 2π, x = π/3, 5π/3 Ans: For 0...

    5 Answers · Science & Mathematics · 13/09/2019

  4. h = kt+c at t=0, h = 2500 m slope = k = –150 m/min h = –150t+c 2500 = –150•0 + c c = 2500 therefore equation is h = –150t + 2500 meters

    1 Answers · Science & Mathematics · 11/09/2019

  5. ... SOLUTION: I like to use this notation: C(n, k) = n! / [(n - k)! k!] That would mean: C(n, n - k) = n! / [(n...;--> {A, B, C} So C(n,k) = C(n, n-k)

    6 Answers · Science & Mathematics · 12/09/2019

  6. (x - h)^2 + (y - k)^2 = r^2 (6 - h)^2 + (5 - k)^2 = r^2 (-3 - h)^2 + (2 - k)^2 = r^2 (-2 - h)^2 + (1 - k)^2 = r^2 (6 - h)^2 + (5 - k)^2 = (-3 - h...6k = 0 48 - 18 - 6k = 0 30 - 6k = 0 6k = 30 k = 30/6 k = 5 (6 - 1)^2 + (5 - 5)^2 = r^2...

    2 Answers · Science & Mathematics · 09/09/2019

  7. ...gt; and <b> are non-parallel, then j<a> + k<b> = 0, if j = k = 0 If j = (m+n+1) and k = -(3n+2), then...

    2 Answers · Science & Mathematics · 06/09/2019

  8. 8 = 65536(1/2)^r 2^3 = (2^16)(1/2)^r (1/2)^-3 = (1/2)^-16 * (1/2)^r -3 = -16 + r r = 13 13 = log(1/k)/log(1/2) 13 = log(base 1/2)(1/k) (1/2)^13 = 1/k k = 8192

    1 Answers · Science & Mathematics · 05/09/2019

  9. ...and 2 points. Set up a system of equations, solve for c and k, then find T(0) 415 = 75 + c * e^(-10k) 340 = c * e^(-10k) 347 = 75 + c * e^(-20k...

    2 Answers · Science & Mathematics · 04/09/2019

  10. 30000 = 25000 * e^(0.0198 * t) 6 = 5 * e^(0.0198 * t) 1.2 = e^(0.0198 * t) ln(1.2) = 0.0198 * t t = ln(1.2) / 0.0198 t = ln(k) / 0.0198 What is k equal to?

    2 Answers · Science & Mathematics · 03/09/2019

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