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...sum of each row is 10 higher than the sum of the previous row (you add

**k**on the left but and you drop**k**-10 on the right which is a difference of**k**- (**k**...2 Answers · Science & Mathematics · 18/07/2019

...(m,s−1) (2k−1)C(2n,2k−1) = (2n−2k+2)C(2n,2k−2) = 2(n−

**k**+1)C(2n,2k−2) for n≥**k**≥1 (2k−1) is odd hence 2 | C(2n...2 Answers · Science & Mathematics · 13/07/2019