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... compute "6 choose 3". You can use the formula: nCk = n! / (

**k**! (n-**k**)!) But rather than using that complicated formula, here...1 Answers · Science & Mathematics · 23/06/2019

(8.9 - 7.9) / 0.5 = 1 / 0.5 = 2 (6.9 - 7.9) / 0.5 = -1 / 0.5 = -2 1 - 1/

**k**^2**k**= 2, because we're looking at values between 2 sd from the mean 1 - 1/2^2 => 1 - 1/4 => 3/4 => 0.75 75%, at least, will be between 6.9 and 8.92 Answers · Science & Mathematics · 18/06/2019

...f' = x – (1/3)x³ + 1 f = (1/2)x² – (1/12)x⁴ + x +

**k**A) a stationary point of a differentiable function of one variable is a point...1 Answers · Science & Mathematics · 19/06/2019

... 488 of them to *exclude*. In general: nCk = nC(n-

**k**) For example, if you had 5 people and you were choosing...2 Answers · Science & Mathematics · 24/06/2019

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