then f(-2) = 0 or (-2)^4 -

**k***(-2)^3 + 1 = 0 16 - 8k + 1 = 0**k**= -17/82 Answers · Science & Mathematics · 07/06/2019

https://www.wolframalpha.com/input/?i=sum(1%2F(4%5E(

**k**)+*+**k**!)+,+**k**+%3D+0+,+**k**+%3D+infinity) e^(1/4)2 Answers · Science & Mathematics · 07/06/2019

(1/√3)(- i + j +

**k**)2 Answers · Science & Mathematics · 18/06/2019

... that when the walker moves from a vertex ,

**k**vertices out of n-1 vertices are non...2u + 3u^2 + ...] = (1-u)[1/(1-u)^2] ← see (note) = 1/(1-u) = 1/[**k**/(n-1)] = (n-1)/**k**And**k**changes from n-1 to...1 Answers · Science & Mathematics · 06/06/2019

Vertex (h,

**k**) = (-5,1) -p = Distance from the vertex to the directrix = -5+7/2 p = -3/2 4p...3 Answers · Science & Mathematics · 17/06/2019

...which will satisfy the original equation unless required otherwise. θ = 3π/4 + 2kπ,

**k**∈ℤ together with θ = 3π/4 + 2kπ,**k**∈ℤ Is the set of all...8 Answers · Science & Mathematics · 05/06/2019

Relationship between abscissas: p +

**k**= 6 Relationship between ordinates: 3 + 2k = p for some real value of**k**(that we now cancel out via substitution) 3 + 2(6 - p) = p 15 = 3p p = 58 Answers · Science & Mathematics · 23/05/2019

...subject to (x-2)^2 + y^2 - 2 = 0 We form L(x,y) = x^2 + (y-14)^2 -

**k**( (x-2)^2 + y^2 - 2 ) Diff wrt**k**Lk = (x-2)^2 + y^2 - 2 = 0...1 Answers · Science & Mathematics · 14/06/2019

...approximately equal to 2.71828 t is the amount of time (in this case years)

**k**is the decay (or grown if positive) constant. Looking at the graph...3 Answers · Science & Mathematics · 13/06/2019

...39; + 2X = 0, assume X = e^(kt), you get 2k^2 + 5k + 2 = 0 => (2k + 1)(

**k**+ 2) = 0 =>**k**= -1/2 or -2. So X_h = Ae^(-1/2 t) + Be...2 Answers · Science & Mathematics · 26/05/2019

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