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  1. ... SOLUTION: I like to use this notation: C(n, k) = n! / [(n - k)! k!] That would mean: C(n, n - k) = n! / [(n...;--> {A, B, C} So C(n,k) = C(n, n-k)

    6 Answers · Science & Mathematics · 12/09/2019

  2. y = 4x - 8 The inverse is: x = 4y - 8 x + 8 = 4y y = (x + 8) / 4 y = (1/4)x + 2 So k = 2

    3 Answers · Science & Mathematics · 28/08/2019

  3. (x - h)^2 + (y - k)^2 = r^2 (6 - h)^2 + (5 - k)^2 = r^2 (-3 - h)^2 + (2 - k)^2 = r^2 (-2 - h)^2 + (1 - k)^2 = r^2 (6 - h)^2 + (5 - k)^2 = (-3 - h...6k = 0 48 - 18 - 6k = 0 30 - 6k = 0 6k = 30 k = 30/6 k = 5 (6 - 1)^2 + (5 - 5)^2 = r^2...

    2 Answers · Science & Mathematics · 09/09/2019

  4. ...and 2 points. Set up a system of equations, solve for c and k, then find T(0) 415 = 75 + c * e^(-10k) 340 = c * e^(-10k) 347 = 75 + c * e^(-20k...

    2 Answers · Science & Mathematics · 04/09/2019

  5. .... So you can reduce this to: kC3 / 10C3 kC3 = k(k-1)(k-2) / 3! 10C3 = 10*9*8 / 3! When you divide, the 3! will cancel...

    2 Answers · Science & Mathematics · 01/09/2019

  6. ...guess that those deltas are difference operators, with Δy_k = y_(k+1) - y_k and Δ²y_k = Δy_(k+1) - Δy_k...

    1 Answers · Science & Mathematics · 16/09/2019

  7. ...1), ... , X(8) has just two elements (a.k.a. "states"): 1 and 2; so its transition...k)=2 and X(k+1)=2} = 4. #{k∈{1, ... , 7} : X(k)=2 and X(k+1)=1} = 1. Finally, recall that...

    1 Answers · Science & Mathematics · 16/09/2019

  8. ...0 < n/d < 1 . Take a positive number k so that 1/k < n/d < 1/(k-1) . n/d - 1/k = (nk...

    2 Answers · Science & Mathematics · 01/09/2019

  9. ...sin(pi/12)^2 * cos(pi/12)^2 1/16 = (1 - cos(pi/12)^2) * cos(pi/12)^2 cos(pi/12)^2 = k (1/16) = (1 - k) * k 1 = 16 * k * (1 - k) 1 = 16k - 16k^2 16k^2 - 16k + 1 = 0 k = (16...

    1 Answers · Science & Mathematics · 25/08/2019

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