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  1. then f(-2) = 0 or (-2)^4 - k*(-2)^3 + 1 = 0 16 - 8k + 1 = 0 k = -17/8

    2 Answers · Science & Mathematics · 07/06/2019

  2. https://www.wolframalpha.com/input/?i=sum(1%2F(4%5E(k)+*+k!)+,+k+%3D+0+,+k+%3D+infinity) e^(1/4)

    2 Answers · Science & Mathematics · 07/06/2019

  3. ... that when the walker moves from a vertex , k vertices out of n-1 vertices are non...2u + 3u^2 + ...] = (1-u)[1/(1-u)^2] ← see (note) = 1/(1-u) = 1/[k/(n-1)] = (n-1)/k And k changes from n-1 to...

    1 Answers · Science & Mathematics · 06/06/2019

  4. Vertex (h,k) = (-5,1) -p = Distance from the vertex to the directrix = -5+7/2 p = -3/2 4p...

    3 Answers · Science & Mathematics · 17/06/2019

  5. ...which will satisfy the original equation unless required otherwise. θ = 3π/4 + 2kπ, k∈ℤ together with θ = 3π/4 + 2kπ, k∈ℤ Is the set of all...

    8 Answers · Science & Mathematics · 05/06/2019

  6. Relationship between abscissas: p + k = 6 Relationship between ordinates: 3 + 2k = p for some real value of k (that we now cancel out via substitution) 3 + 2(6 - p) = p 15 = 3p p = 5

    8 Answers · Science & Mathematics · 23/05/2019

  7. ...subject to (x-2)^2 + y^2 - 2 = 0 We form L(x,y) = x^2 + (y-14)^2 - k( (x-2)^2 + y^2 - 2 ) Diff wrt k Lk = (x-2)^2 + y^2 - 2 = 0...

    1 Answers · Science & Mathematics · 14/06/2019

  8. ...approximately equal to 2.71828 t is the amount of time (in this case years) k is the decay (or grown if positive) constant. Looking at the graph...

    3 Answers · Science & Mathematics · 13/06/2019

  9. ...39; + 2X = 0, assume X = e^(kt), you get 2k^2 + 5k + 2 = 0 => (2k + 1)(k + 2) = 0 => k = -1/2 or -2. So X_h = Ae^(-1/2 t) + Be...

    2 Answers · Science & Mathematics · 26/05/2019

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