... to the field there. field E =

**k**Q / r² where**k**= 1/4πε₀ = 8.99e9 N·m²/C² and r = d*cos30º = d...3 Answers · Science & Mathematics · 22/01/2021

...; (a) T = 0.216 so ω = 2π/0.216 = 29.1rad/s ω² =

**k**/m so**k**= 29.08² * 0.327 = 276.7 Force Constant**k**= ...1 Answers · Science & Mathematics · 22/01/2021

With a frictionless surface, the ball merely slides (not rolls); the initial spring energy is converted into PE: ½

**k**x² = mgh ½ * 500N/m * (0.25m)² = 1**k**g * 9.8m/s² * h → → h = 1.6 m1 Answers · Science & Mathematics · 22/01/2021

.../I = 1.6 / 20.2 µA = 0.079 MΩ or 79

**k**Ω1 Answers · Science & Mathematics · 21/01/2021

.... PS = PE ½

**k**x² = mg(h + x)**k**= 2mg(h + x) / x²**k**= 2(0.142)(9.8)(0.622 + 0.0435501) / 0....2 Answers · Science & Mathematics · 20/01/2021

The potential energy in the compressed spring becomes potential energy of the ball: ½

**k**x² = mgh You are given**k**, m (convert to**k**g), and h, and you**k**now g. Solve for x.1 Answers · Science & Mathematics · 19/01/2021

S = (8πhc²/λ⁵) / (e^[hc/(λ

**k**T)] - 1) When I plug in all relevant variables and do the necessary unit conversions, I get S = 34 W/cm²·nm which matches none of your choices but...2 Answers · Science & Mathematics · 19/01/2021

The work done BY the gas would be W = integral from v1 to v2 of p dv, but p = nRT/v = (p1 v1)/v. So you want the integral of (p1 v1) dv/v, which comes out to (p1 v1)*ln(v2/v1) = (140000 Pa)(0.77 m^3)*ln(0.26/0.77) = -117 kJ. Then the work done ON...

1 Answers · Science & Mathematics · 17/01/2021

When T is constant, then pV is also constant. p(final) = (2.22 atm)*(1/1.38) = around 1.6 atm but use a calculator.

1 Answers · Science & Mathematics · 17/01/2021

specific heat capacity of coffee cc = cw = 4.186 joule/(g*°C) 4.186(mc*80+(250-mc)*10) = 4.186*60*(mc+250-mc) 4.186 cancels 70mc+2500 = 60*250 mass of coffee mc = (60*250-2500)/70 = 179 grams mass of water mw = 250-179 = 71 grams

2 Answers · Science & Mathematics · 15/01/2021