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1. ### A model car of mass 5kg slides down a frictionless ramp into a spring with constant k =4.9kN/m. ?

a) GPE became SPE mgh = ½kx² 5kg * 9.8m/s² * h = ½ * 4900N/m * (0.22m)² = 119 J h = 2.42 m b) a = F/m = kx / m = 4900N/m * 0.22m / 5kg = 216 m/s² c) GPE = SPE + KE 119 J...

1 Answers · Science & Mathematics · 11/10/2020

2. ### Conservation of energy and spring?

ω = √( k /m) = √(5kg/s² / 0.25kg) = 4.47 rad/s Measured from the new equilibrium...

1 Answers · Science & Mathematics · 24/09/2020

3. ### A spring hangs from a support, at rest. If you suspend a 0.46kg mass from it, its deflection is 7.9cm.?

the equation: k = – F/x. Where k is the spring constant, F is the force applied over x, and x is the displacement by the spring F =mg Subbing in we get k = mg/x N/m So make sure to convert cm to m

1 Answers · Science & Mathematics · 15/10/2020

4. ### A lawnmower weighing 12kg is pushed by a force of 150N horizontally and 40N down. If the coefficient of kinetic friction between wheels?

friction = µ k * normal force f = µ k * (mg +Fy) = 0.9*(12kg*9.8m/s² + 40N) = 142 N acceleration = net force / mass a = (150N - 142N) / 12kg = 0.68 m/s²

1 Answers · Science & Mathematics · 01/10/2020

PE = .5kx^2 where k is a constant and x is the length stretched PE= mgh...

1 Answers · Science & Mathematics · 12/10/2020

6. ### How do you find the max compression of a spring using Law of conservation of energy?

...difference must be absorbed by the spring. then use E = ½kd²   k is spring constant in N/m you are missing k , but you need...

2 Answers · Science & Mathematics · 16/10/2020

7. ### Block on block forces Problem?

... from ma = 7*3 = 21N  But the net force = F - mg*μ k   -> F = 21 + 7*9.8 * 0.2  ~= 34.7N To accelerate the small block...

1 Answers · Science & Mathematics · 14/10/2020

8. ### You throw your shoe into the closet. It starts across the floor at 1.5m/s. If the shoe weighs 200g and the kinetic friction coefficient ?

By kinematics: acceleration = net force / mass = -µ k *m*g / m = -µ k *g a = -0.15 * 9.8m/s² = -1.47 m/s² ...

1 Answers · Science & Mathematics · 01/10/2020

9. ### A 105kg swimmer stands on a diving board with spring constant of 7.6 x 10^3 N/m. Determine the period and frequency of the board vibrations.?

frequency f = (1/2π)*√( k /m) + (1/2π)*√(7600kg/s² / 105kg) f = 1.35 Hz ◄ period T = 1/f = 0.739 s ◄ Hope this helps!

1 Answers · Science & Mathematics · 12/10/2020

10. ### A mass vibrates in simple harmonic motion at the end of a spring. When the displacement of the mass from equilibrium is 2cm, elastic energy?

use the energy to get spring constant PE = ½kd² = 18 k = 2•18/0.02² = 90000 N/m f = (1/2π)√( k /M) = 4 √( k /...

1 Answers · Science & Mathematics · 16/10/2020