Vitamin

**K**aids in blood clotting: when the body is injured, vitamin... before surgery to prevent excessive bleeding. Vitamin**K**also helps the body absorb calcium and it has been suggested...4 Answers · Science & Mathematics · 06/09/2010

Help finding

**k**? For the first-order decomposition of N2O5 at a high temperature...keep getting it wrong and Idk how. ln(.32/.88)=-k175 ln(.32/.88)/175=-**k**\**k**=5.78 x 10^-3 but the answer is 3.31 X 10^-3...2 Answers · Science & Mathematics · 09/07/2014

Rate =

**k*** [NO]^m * [H2]^n 0.00123 =**k*** 0.1^m * 0.1^n -------------------(1) 0.00246 =**k*** 0.1^m * 0.2^n -------------------(2) 0.00492 =**k*** 0.2^m * 0.1^n -------------------(3) Divide (1) by (2) 0.00123/0.00246 =**k**...3 Answers · Science & Mathematics · 06/02/2007

if you start with... -d[A] / dt =

**k**x [A]² x [B] x [C] we need to get...] + 1/9 [A]² and then... -d[A] / dt =**k**x [A]² x [B] x [C] becomes...1 Answers · Science & Mathematics · 27/10/2010

the "

**k**" is the constant we insert to solve the proportionality... read on ***** the...constant to ma**k**e the equation an equality. In this case, the constant is**k**and.. rate α [A] becomes... rate =**k**x [a] now because we have...1 Answers · Science & Mathematics · 20/09/2012

If you define

**K**for the first reaction as K1 and for the second as K2..., thus it will be the same as dividing by K2. So**K**for your final reaction will be: (0.0334)^2 / 2.35 = 4.75 * 10^-42 Answers · Science & Mathematics · 12/05/2007

**K**is the equilibrium constant for a reaction and Q is the reaction quotient.... Suppose you have a reaction A<-->B**K**= [B]/[A] when the reaction is at equilibrium. If**K**...1 Answers · Science & Mathematics · 01/05/2016

Your equation for

**K**is:**K**= { [SO3] [NO] } / { [SO2] [NO2...as the reaction proceeds toward equilibrium. Plug into the equation for**K**all your starting values and let x represent the concentration change...3 Answers · Science & Mathematics · 18/02/2013

**K**α radiation comes from the emission of a photon that occurs when an excited atom with a "hole...square of a quantity one less than the atomic number of the element in question (atomic number minus 1)."**K**-alpha for scandium (Z = 21) is thus estimated as (10.2 eV)(20)² = 4080 eV...3 Answers · Science & Mathematics · 22/04/2010

**K**(s) + AgNO3(aq) => KNO3(aq) + Ag(s)1 Answers · Science & Mathematics · 21/04/2015