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1. ### Suppose k is an approximation to sq. root of 2.?

Assume | k −√2| < ϵ. Need to prove that | ( k +2)/( k +1)−√2... from | k −√2| < ϵ assemble an expression for ( k +2)/( k +1)−√2 | k −√2| < ϵ → √2−ϵ &...

1 Answers · Science & Mathematics · 28/02/2013

2. ### how do you solve for " k " in the equation below?

... 6/( k +1) - 1/( k ) = 1 ← note: k ≠ 0 or -1 or 6( k ) - ( k +1) = ( k +1)( k ) or 6k - k - 1 = k² + k or 0 = k² + k - 6k + k ...4*3 ) ] / 2 k = [ 4 ± 2√3 ) ] / 2 k = 2 ± √3 k = { 2 - √3, 2 + √3 } k ~ { 0.2679, 3.7321 }

3 Answers · Science & Mathematics · 11/09/2010

3. ### log(base2)x+log(base2)(x+5)= k ?

"Solve for k in terms of k " doesn't make sense: k = k is obvious. I...thing and see if we can get a cleaner statement of the relationship between x and k : log(base2)x+log(base2)(x+5)= k log(base2) [x(x+5)] = k {by properties of...

2 Answers · Science & Mathematics · 19/10/2009

4. ### Analysis: Prove that K is compact if and only if every sequence in K has a subsequence that converges to?

This only true if K is also a metric space. Otherwise there are counterexamples.... Now to prove the claim: Forward direction: Suppose K is compact and A = (x_n) is a sequence in K . We...

2 Answers · Science & Mathematics · 16/10/2010

5. ### Does the series Sum ( k =2, oo) 1/((ln( k ))^ln( k )) converge diverge or?

a[ k ] = 1/ln( k )^ln( k ) a[ k +1] = 1/ln( k (1+1/ k ))^ln( k +1) = 1/( ln( k ) + ln(1+1/ k ))^ln( k +1) = 1/ ( ln( k )^ln( k +1) ( 1+ (ln(1+1/ k )/ln( k ) )^ln( k +1) a[ k ]/a[ k +1] =ln( k )(1+(ln...

3 Answers · Science & Mathematics · 18/04/2007

6. ### If the sum of k multiplied by three and k is 12,?

" k multiplied by three": 3k "the sum of k multiplied by three and k ": 3k + k "the sum of k multiplied by three and k is 12": 3k + k = 12 3k + k = 12 4k = 12 k = 12/4 k = 3

2 Answers · Science & Mathematics · 22/04/2012

7. ### How to solve x^n = k ?

It depends on what k can be. Is k always a positive integer? Is k always a negative integer...a positive integer. Since 1 = cos 0 + i sin 0, we see that, in polar form: k = k (cos 0 + i sin 0). By DeMovire's Theorem: x...

1 Answers · Science & Mathematics · 28/03/2011

8. ### Math- Equation solving for k ?

========= x^2 + k + 6 = kx +3x x^2 -x( k +3) + ( k +6) = 0 The equation will have equal ... happens when the discriminant is zero. So, solve ( k +3)^2 - 4( k +6) = 0 k ^2 + 6k + 9 - 4k - 24 = 0 k ^2 + 2k - 15 = 0 ( k +5)( k -3...

2 Answers · Science & Mathematics · 14/10/2012

9. ### Find the set of values of k ?

y = 2x + k ← this is a line y = x² + kx + 5 ← this is a curve y = y → 2 points → 2 solutions for x x² + kx + 5 = 2x + k x² + kx + 5 - 2x - k = 0 x² + x.( k - 2) + (5 - k ) = 0 Polynomial...

3 Answers · Science & Mathematics · 22/01/2016

10. ### Find the value of k such that ( k , k ) is equidistant from (−3, 0) and (0, 6)?

... D between two points = sqrt[(x-x1)^2 +(y-y1)^2] D = sqrt[( k +3)^2 +( k -0)^2] = sqrt[( k -0)^2 +( k -6)^2] sqrt[( k +3)^2 +( k -0)^2] = sqrt[( k -0)^2...

4 Answers · Science & Mathematics · 12/09/2010