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...for both charges. Sum the horizontal components: Ex = (

**k***4e-6/18) * cos45 +**k***4e-6/18 *cos135 =**k***4e-6/18 *[0.7071-0.7071] = 0 Sum...1 Answers · Science & Mathematics · 01/09/2019

...the field due to the other two corner charges: kQ / (2L²) = 2*

**k***10nC*cos45º / L² which leads directly to Q...1 Answers · Science & Mathematics · 01/09/2019

...with q1 in place and then you bring in q2, the new potential energy is PE =

**k***q1*q2 / (0.200m*√2) and if you then bring in q3, you have PE' = PE...1 Answers · Science & Mathematics · 01/09/2019

... is force in newtons r is separation in meters

**k**= 8.99e9 Nm²/C²1 Answers · Science & Mathematics · 31/08/2019

... is force in newtons r is separation in meters

**k**= 8.99e9 Nm²/C²1 Answers · Science & Mathematics · 29/08/2019

... vector arithmetic. for the left charge Ex = 2µ

**k**/r² pointed right Ey = 0 for the right charge... in Newtons/coulomb OR volts/meter**k**= 1/4πε₀ = 8.99e9 Nm²/C²1 Answers · Science & Mathematics · 27/08/2019

...standard temperature and pressure R = gas constant = 286 m²/s²/

**K**for air T = absolute temperature (273.15**K**+ °C) = 298.15**K**...3 Answers · Science & Mathematics · 24/08/2019

... = QE in Newtons/coulomb OR volts/meter

**k**= 1/4πε₀ = 8.99e9 Nm²/C² re the other problem, just use...2 Answers · Science & Mathematics · 23/08/2019

Potential energy of the spring at max compression is kx^2 / 2. This gets turned to gravitational potential energy at the top of the incline with no friction h = kx^2 / (2mg)

1 Answers · Science & Mathematics · 23/08/2019

... following equation is used to solve this problem. F =

**k*** Q1 * Q2 ÷ d^2 I use 9 * 10^9 for**k**. The unit of the...2 Answers · Science & Mathematics · 16/08/2019