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**K**is large. By definition of what an equilibrium constant is it ...coefficient over product of the reactants to the exponent of the coefficient. If**K**is large then the top (products) is large and the bottom (...2 Answers · Science & Mathematics · 17/05/2008

**K**= (products / reactants) raised to their respective... that solids and liquids are not included in**K**expression.**K**= [NH3] [HCl]**K**= [2.0] / [5.0]**K**...1 Answers · Science & Mathematics · 17/08/2009

**K**= propan-2-ol, CH3-CH(OH)-CH3 L = propanone...(-O-CH(CH3)2)(OH)-CH3 Since**K**is an alcohol with MF of C3H8O, the only two possibilities...2 Answers · Science & Mathematics · 29/01/2009

The main formula which relates dG and

**K**is as follows: dG = -RTln... negative. This makes sense because**K**, which is the equilibrium constant for the reaction, ...1 Answers · Science & Mathematics · 25/08/2012

**k**is a constant http://en.wikipedia.org/wiki/Gay-Lussac%27s_law...n and V constant) the effect will be T also changing such that**k**is still the same. And, if you change T, P will change such...2 Answers · Science & Mathematics · 18/04/2011

...re referring to; there are 24 of them. They range from

**K**-32 to**K**-55, so each has a different number of protons...3 Answers · Science & Mathematics · 23/12/2011

... in the problem. The correct value is R = 8.314 J/

**K***mol. Free energy of formation = dG = -RTlnK, where**K**...2 Answers · Science & Mathematics · 02/11/2010

The size of

**K**depends on the relative concentrations of reactions and...concentration of reactants and products are similar at equilibrium,**K**will be approximately equal to 1. ... When the concentration of products...2 Answers · Science & Mathematics · 03/03/2007

Li and

**K**have one valence electron each. I hope you can follow what I'm ...7 Answers · Science & Mathematics · 06/09/2009

**K**is the ratio between the product of concentration of products and product of concentration of reactants.**K**= [products]/[reactants] =1 means products and ...2 Answers · Science & Mathematics · 16/02/2011