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...rate constants are related to the half-life of the reaction by

**k**= ln 2 / half-life. So, at 300**K**,**k**= (ln 2) / 2.50X10^4 = 2...2 Answers · Science & Mathematics · 14/06/2019

... only given two values of T and two values of

**k**, you can use the form of the Arrhenius equation that is: ln (k2/k1...1 Answers · Science & Mathematics · 08/02/2019

From the first half life, calculate the rate constant as

**k**= ln 2 /t1/2 k1 = ln 2 / 2.14X10^4 = 3.24X10^-5 s^-1 Now...1 Answers · Science & Mathematics · 10/06/2019

8.51g/L at 52.0 Celsius and 88.6

**k**/Pa. <<< did you mean...4 Answers · Science & Mathematics · 28/07/2019

Distribute the negative, Then, add like items. (2k^2 +

**k**+ 5) - (8 + 4k -**k**^2) (2k^2 +**k**+ 5) - 8 - 4k +**k**^2 3k² -3k -35 Answers · Science & Mathematics · 14/02/2019

... during the reaction = 25 min. A1 = concentration of the reactant at time t, = ?

**K**= velocity constant = 0.784hr^-1 = 0.013 min^-1 Rearranging the abobve equation...2 Answers · Science & Mathematics · 08/02/2019

x^2 - x + 1 >= x^2 -kx -1 - x >= -kx - 2 kx - x >= -2 x(

**k**- 1) >= -2 for x >0 ...**k**>= (-2/x) + 1 <<...1 Answers · Science & Mathematics · 10/11/2018

y = 4x - 8 The inverse is: x = 4y - 8 x + 8 = 4y y = (x + 8) / 4 y = (1/4)x + 2 So

**k**= 23 Answers · Science & Mathematics · 28/08/2019

... / RT = (1.85 atm) x (1.05 L) / ((0.082057338 L atm/

**K**mol) x (263**K**)) = 0.0900 mol b) (0.993 atm) x (1.00 L) / ((0.082057338...1 Answers · Science & Mathematics · 16/03/2019

Δq = (20.8 J/mol

**K**) x (0.25 g He / (4.0026 g He/mol)) x (310.0**K**- 230.0**K**...1 Answers · Science & Mathematics · 10/05/2019