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  1. ...rate constants are related to the half-life of the reaction by k = ln 2 / half-life. So, at 300 K, k = (ln 2) / 2.50X10^4 = 2...

    2 Answers · Science & Mathematics · 14/06/2019

  2. ... only given two values of T and two values of k, you can use the form of the Arrhenius equation that is: ln (k2/k1...

    1 Answers · Science & Mathematics · 08/02/2019

  3. From the first half life, calculate the rate constant as k = ln 2 /t1/2 k1 = ln 2 / 2.14X10^4 = 3.24X10^-5 s^-1 Now...

    1 Answers · Science & Mathematics · 10/06/2019

  4. Distribute the negative, Then, add like items. (2k^2 + k + 5) - (8 + 4k - k^2) (2k^2 + k + 5) - 8 - 4k + k^2 3k² -3k -3

    5 Answers · Science & Mathematics · 14/02/2019

  5. ... during the reaction = 25 min. A1 = concentration of the reactant at time t, = ? K = velocity constant = 0.784hr^-1 = 0.013 min^-1 Rearranging the abobve equation...

    2 Answers · Science & Mathematics · 08/02/2019

  6. x^2 - x + 1 >= x^2 -kx -1 - x >= -kx - 2 kx - x >= -2 x(k - 1) >= -2 for x >0 ... k >= (-2/x) + 1 <<...

    1 Answers · Science & Mathematics · 10/11/2018

  7. y = 4x - 8 The inverse is: x = 4y - 8 x + 8 = 4y y = (x + 8) / 4 y = (1/4)x + 2 So k = 2

    3 Answers · Science & Mathematics · 28/08/2019

  8. ... / RT = (1.85 atm) x (1.05 L) / ((0.082057338 L atm/K mol) x (263 K)) = 0.0900 mol b) (0.993 atm) x (1.00 L) / ((0.082057338...

    1 Answers · Science & Mathematics · 16/03/2019

  9. Δq = (20.8 J/mol K) x (0.25 g He / (4.0026 g He/mol)) x (310.0 K - 230.0 K...

    1 Answers · Science & Mathematics · 10/05/2019

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