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  1. a=dv/dt=g-kv. Put y=g-kv. dy/dt= - k dvdt=-ky dy/dt= -k, y=y0 exp (-kt). This gives g-kv= y0 exp(-kt) kv...

    2 Answers · Science & Mathematics · 11/02/2019

  2. From ω=√︎(k/μ) you see that you have to assess how μ changes from CH to CT...

    1 Answers · Science & Mathematics · 13/09/2019

  3. ... + 492N*sin31º = 600 N friction force f = µk*Fn = 0.59 * 600N = 354 N net horizontal force Fnet = ...

    1 Answers · Science & Mathematics · 28/05/2019

  4. From Q, the force = k* Q*2Q/L² at 0° From 4Q, the force = k*...

    1 Answers · Science & Mathematics · 02/05/2019

  5. field E = vector Σ kQ / d² where k = 8.99e9 N·m²/C² x-direction: The two charges on the...

    1 Answers · Science & Mathematics · 10/09/2019

  6. ... many kinds of plywood. I found this, 0.13 W/m•K but that may not match your number. 58-cm2 ?? guessing that thus...

    1 Answers · Science & Mathematics · 12/02/2019

  7. ...position s(t) = ∫ v(t) dt s(t) = ∫ [2sin(t) i + 2cos(t) j + t k] dt = -2cos(t) i + 2sin(t) j + ½t² k + C...] and so unit T(t) = [2sin(t) i + 2cos(t) j + t k] / √[4 + t²] d) the tangential component of the acceleration...

    1 Answers · Science & Mathematics · 29/06/2019

  8. electrostatic force F = kQq / d² where k = 8.99e9 N·m²/C² first condition: -0.119 N = 8....

    2 Answers · Science & Mathematics · 05/09/2019

  9. ...the event. from the preliminary test, we can find the spring constant k by summing forces to zero. kx - mg = 0 kx = mg...by the cord at max stretch is F = kx F = (k'/25.1)(30.4) F = (5(mg/1.65)/25.1)(30.4) F...

    4 Answers · Science & Mathematics · 07/10/2019

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