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(k + 2)/3 = k/2 - 2 k + 2 = 3/2*k - 6 2 = 1/2*k - 6 8 = 1/2*k k = 16
3 Answers · Science & Mathematics · 02/03/2009
K word ?? Got me I know the F word and the C word And the B words but the K word what Kitten ?
6 Answers · Society & Culture · 19/10/2008
Goal: To get "k" isolated by itself. a.) 0 = 14 + k In order to isolate... so that the 3.3 on the variable side will turn into 0 and will not count. -0.8 = k + 3.3 -0.8 - 3.3 = k + 3.3 - 3.3 -4.1 = k + 0 Since the zero does...
3 Answers · Science & Mathematics · 16/06/2011
k(x) = x² - 6 k(x - 1) = (x - 1)² - 6 k(x - 1) = x² - 2x + 1 - 6 k(x...2(2x + 4) + 4 h(h(x)) = 4x + 8 + 4 h(h(x)) = 4x + 12 h(x) = 2x + 4, k(x) = x² - 6 h(k(x)) = 2(x² - 6) + 4 h(k(x)) = x²...
2 Answers · Science & Mathematics · 21/09/2012
(k - 2)x^2 + (k - 5)x - 5 = 0 The roots are equal if the discriminant... discriminant, b^2 - 4ac, evaluated as follows: (k - 5)^2 - 4(k - 2)(-5) And we want this to be equal to zero. (k...
3 Answers · Science & Mathematics · 06/12/2008
In ecology, K selection theory relates to the selection of combinations of ...to drive evolution in one of two generalized directions: r- or K-selection. These terms, r and K, are derived from...
3 Answers · Science & Mathematics · 14/10/2009
k ∫ (2kx - x^2)dx = 18 0 ....................k (kx^2 - x^3/3) | = 18 ....................0 k(k^2) - k^3/3 - (k(0^2) - 0^3/3) = 18...
1 Answers · Science & Mathematics · 02/05/2011
...e^(kx) - e^(-kx) ] / [ e^(3x) + e^(-3x) ] When x is large and assume k >= 0 sinh(kx) / cosh(3x) ≈ e^(kx) / e^(3x) = e^(x(k - 3)) For sinh(kx...
1 Answers · Science & Mathematics · 21/02/2019
I love K-Pop more than American Pop and most of the highest...K-Pop is crazy (in a good way), since there are so many new K-Pop groups and artists coming out so often, that ...
14 Answers · Entertainment & Music · 26/11/2011
-k^3 + k^2pk - pk +p^2 = 0 p^2 + pk (k^2 - 1) - k^3 = 0 Solve for p by using the quadratic... up my own problem: The second term "k^2pk" looks very strange, so I will suppose it ...
1 Answers · Science & Mathematics · 06/10/2009