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...force = Static frictional force kx = μ(s)N kx = μ(s)mg x = μ(s)mg/

**k**x = 0.60*1.5*9.8/(1.2 x 10³) x = 0.00735 m or 7.35 mm The block...2 Answers · Science & Mathematics · 20/10/2019

L = Lo*(1+

**k***ΔT) L = 120*(1+17*10^-6*(24-21)) = 120.006 mm lenght increases by 6 μm1 Answers · Science & Mathematics · 20/10/2019

tangential velocity Vt = ω*r = 23*1.75 m/sec

**K**e = m/2*V^2 = 18/2*(23*1.75)^2 = 14,581 joule or J = m*r^2 = 18*49/16**K**E = J/2*ω^2 = 9*49/16*23^2 = 14,581 joule1 Answers · Science & Mathematics · 17/10/2019

a. field E = σ / ε where ε =

**k***ε₀ so σ = Eε = 1.5e6N/C * 5*8.85e-12 C²...1 Answers · Science & Mathematics · 13/10/2019

...8200/18200)^2 this goes into the spring. 1/2 kx^2 = 1/2 m v^2 x^2 = m v^2 /

**k**x = sqrt( m v^2 /**k**) = sqrt( 18200*(8.3 * 8200/18200)^2 / (3.2 * 10 ^ 5) ) = 0.89 m...2 Answers · Science & Mathematics · 11/10/2019

...the event. from the preliminary test, we can find the spring constant

**k**by summing forces to zero. kx - mg = 0 kx = mg...by the cord at max stretch is F = kx F = (**k**'/25.1)(30.4) F = (5(mg/1.65)/25.1)(30.4) F...4 Answers · Science & Mathematics · 07/10/2019

...dv/dx = -kx + 4.2 we want the point where dv/dx = 0, which is where x = 4.2 /

**k**= 4.2 / 1100 = 0.0038 m = 0.38 cm ½mv² = 0.22 - ½...1 Answers · Science & Mathematics · 18/10/2019

... = 8.314 J/mol·K So you can compute the temperature change in

**K**(which is the same as the temperature change in ºC, since for CHANGES...1 Answers · Science & Mathematics · 24/09/2019

...x / √(x²+y²) So, for Ey I get dEy =

**k***λ*dx*y / (x²+y²)^(3/2) so Ey =**k***λ*y ∫ dx / (x²...3 Answers · Science & Mathematics · 23/09/2019

... / A₂Y₂ for nylon ₁ + and copper ₂ 1m * 5e-5/

**K*** -20K + 1m * 1.6e-5/**K*** -20K = F₁*1m / (π/4)(0.005m...1 Answers · Science & Mathematics · 21/09/2019

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