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1. ### Suppose k is an approximation to sq. root of 2.?

Assume |k−√2| < ϵ. Need to prove that | (k+2)/(k+1)−√2... from |k−√2| < ϵ assemble an expression for (k+2)/(k+1)−√2 |k−√2| < ϵ → √2−ϵ &...

1 Answers · Science & Mathematics · 28/02/2013

2. ### how do you solve for "k" in the equation below?

... 6/(k+1) - 1/(k) = 1 ← note: k ≠ 0 or -1 or 6(k) - (k+1) = (k+1)(k) or 6k - k - 1 = k² + k or 0 = k² + k- 6k + k...4*3 ) ] / 2 k = [ 4 ± 2√3 ) ] / 2 k = 2 ± √3 k = { 2 - √3, 2 + √3 } k ~ { 0.2679, 3.7321 }

3 Answers · Science & Mathematics · 11/09/2010

3. ### log(base2)x+log(base2)(x+5)=k?

"Solve for k in terms of k" doesn't make sense: k=k is obvious. I...thing and see if we can get a cleaner statement of the relationship between x and k: log(base2)x+log(base2)(x+5)=k log(base2) [x(x+5)] = k {by properties of...

2 Answers · Science & Mathematics · 19/10/2009

4. ### Analysis: Prove that K is compact if and only if every sequence in K has a subsequence that converges to?

This only true if K is also a metric space. Otherwise there are counterexamples.... Now to prove the claim: Forward direction: Suppose K is compact and A = (x_n) is a sequence in K. We...

2 Answers · Science & Mathematics · 16/10/2010

5. ### Does the series Sum (k=2, oo) 1/((ln(k))^ln(k)) converge diverge or?

a[k] = 1/ln(k)^ln(k) a[k+1] = 1/ln(k(1+1/k))^ln(k+1) = 1/( ln(k) + ln(1+1/k))^ln(k+1) = 1/ ( ln(k)^ln(k+1) ( 1+ (ln(1+1/k)/ln(k) )^ln(k+1) a[k]/a[k+1] =ln(k)(1+(ln...

3 Answers · Science & Mathematics · 18/04/2007

6. ### If the sum of k multiplied by three and k is 12,?

"k multiplied by three": 3k "the sum of k multiplied by three and k": 3k + k "the sum of k multiplied by three and k is 12": 3k + k = 12 3k + k = 12 4k = 12 k = 12/4 k = 3

2 Answers · Science & Mathematics · 22/04/2012

7. ### How to solve x^n = k?

It depends on what k can be. Is k always a positive integer? Is k always a negative integer...a positive integer. Since 1 = cos 0 + i sin 0, we see that, in polar form: k = k(cos 0 + i sin 0). By DeMovire's Theorem: x...

1 Answers · Science & Mathematics · 28/03/2011

8. ### Math- Equation solving for k?

========= x^2 + k + 6 = kx +3x x^2 -x(k+3) + (k+6) = 0 The equation will have equal ... happens when the discriminant is zero. So, solve (k+3)^2 - 4(k +6) = 0 k^2 + 6k + 9 - 4k - 24 = 0 k^2 + 2k - 15 = 0 (k+5)(k-3...

2 Answers · Science & Mathematics · 14/10/2012

9. ### Find the set of values of k?

y = 2x + k ← this is a line y = x² + kx + 5 ← this is a curve y = y → 2 points → 2 solutions for x x² + kx + 5 = 2x + k x² + kx + 5 - 2x - k = 0 x² + x.(k - 2) + (5 - k) = 0 Polynomial...

3 Answers · Science & Mathematics · 22/01/2016

10. ### Find the value of k such that (k, k) is equidistant from (−3, 0) and (0, 6)?

... D between two points = sqrt[(x-x1)^2 +(y-y1)^2] D = sqrt[(k+3)^2 +(k-0)^2] = sqrt[(k-0)^2 +(k-6)^2] sqrt[(k+3)^2 +(k-0)^2] = sqrt[(k-0)^2...

4 Answers · Science & Mathematics · 12/09/2010