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I assume that you want to find the spring constant,

**k**from hooks law. F = kx meaning that there is a linear relationship...1 Answers · Science & Mathematics · 01/11/2013

0

**K**> 0 F > 0 C 273**K**= 0 C 32 F = 0 C 0 C = 0 C1 Answers · Science & Mathematics · 05/07/2011

m = ku+v m =

**k**{1,2,1} + {-2,3,2} m = {**k**-2, 2**k**+3,**k**+2} vector m perpendicular to w if m • w = 0 {**k**-2, 2**k**+3,**k**+2} • {4,-1,3} = 0 5 (**k**-1) = 0**k**= 12 Answers · Science & Mathematics · 28/09/2010

...2 = (kx^2)/2 here m is mass of the ball, v is the initial velocity,

**k**is the spring constant and x is the value of compression=0.62 cm so put...2 Answers · Science & Mathematics · 14/06/2009

Elastic Strain Energy = (1/2)kx^2 where

**k**is the spring constant and x is the extension to work out the extension do...2 Answers · Science & Mathematics · 25/08/2013

Is 10.5 the half life? For any half life the ratio of activity is 0.5 0.5 = e^(10.5k) ln(0.5) = 10.5k

**k**=ln(0.5)/10.51 Answers · Science & Mathematics · 12/12/2011

...ωcos(ωt + φ) x"(t) = -Aω²sin(ωt + φ) ω = √(

**k**/m) ω = √(2/0.5) ω = 2 x'(0.1) = 0.263 = 2Acos(2(0.1...1 Answers · Science & Mathematics · 12/03/2014

After

**k**becomes to big, the force of streching the spring would break it. So yes,**k**could become too big depending on the material Assuming you meant the**k**in F=kx5 Answers · Science & Mathematics · 02/11/2007

...need detA = 0 which gives us: -63 + 7k^2 = 0. Hence

**k**^2 = 9 or**k**= + or -3 (the only two such values.) Graphically ...1 Answers · Science & Mathematics · 03/05/2012

The angular frequency ω = √

**k**/m ω = 7.4 rad /s and**k**= 51N/m m=**k**/ω^2 = 51/7.7/7.4 = 0.9 kg. =============================2 Answers · Science & Mathematics · 07/07/2010