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1. ### Solve k= k+15 divided by 3(k-1) use quadratic formula?

k = (k+15)/3*(k-1) ==> multiply both sides by 3(k-1) to get rid of fractions 3k(k-1) = k+15 ==> expand the LHS 3k^2-3k = k+15 ==> move everything to the LHS 3k^2-4k-15=0 actually this does...

3 Answers · Science & Mathematics · 21/07/2007

2. ### \what is the value of k?

2kx² - 12x + (k+7) = 0 Solve for k b² - 4ac = 0 (b = -12, a = 2k and c = k...8 ..........-k² - 7k + 18 = 0 .......... k² + 7k - 18 = 0 ........ (k - 2) (k + 9) = 0 ......k - 2 = 0.......................... k + 9 = 0 k - 2 + 2 = 0 + 2...

4 Answers · Science & Mathematics · 12/09/2010

3. ### Find every integer k s.t. k>= 3 and k-2 divides 2k?

If k-2 divides 2k, k-2 ≠ 0, then there is an integer i such that 2k = (k-2)i Solving for k gives... of i less than or equal to 1 that produce k≥ 3. Therefore the only ...

1 Answers · Science & Mathematics · 20/03/2009

4. ### Find all the values of k?

∫(x = 0 to 1) x^k ln x dx = ∫(∞ to 0) (e^w)^k * w * (e^w...;==> x = e^w = -∫(w = 0 to ∞) we^((k+1)w) dw = -∫(w = 0 to ∞) we^((k+1)w) dw...1)t))] = (-1/(k+1)^2) * [1 + lim(t→∞) -e^((k+1)t)] = (-1/(k+1)^2) * (1 + 0), since k+1...

3 Answers · Science & Mathematics · 10/06/2015

5. ### Simplify the following factorial:(2k+1)!/(2)(k!)?

(2k+1) * (2k) * (2k-1) * ... * (k+2) * (k+1) / 2 = (2k+1) * k * [(2k-1) * ... * (k+2) * (k+1)] In...ellipsis notation from becoming ambiguous. (Otherwise the k factor is out of sequence and makes that notation unclear.)

1 Answers · Science & Mathematics · 18/07/2011

6. ### How do you solve for K?

K-9/27 =7/9 Step 1, Multiply 27 to the whole entire problem. 27(K-9/27 =7/9) 27K - 9 = 21 Step 2, Add 9 and Divide...

2 Answers · Science & Mathematics · 05/05/2012

7. ### solve for R C=K(Rr/R-r)?

C=K(Rr/R-r) Divide both sides by K: C...r): (R-r)(C/K) = Rr Distribute C/K: CR/K-Cr/K = Rr Subtract Rr...

4 Answers · Education & Reference · 05/10/2009

8. ### Math problem! Please solve for K.?

k^0.5 = 6 square the whole equation (k^0.5 = 6)^2 k = 6^2 k= 36 RainMaker nifty-rainmaker.blogspot.com/

5 Answers · Science & Mathematics · 10/05/2010

9. ### Prove If K is convex, then cl(K) is convex?

Let K be a convex subset of R^p and let x,y be in the closure of K. Then there exist sequences (x_n), (y_n) of points in K such that lim x_n = x and lim y_n = y. The line segment between x_n and y_n...

2 Answers · Science & Mathematics · 20/01/2012

10. ### Finding the value of k?

(k + 2)/3 = k/2 - 2 k + 2 = 3/2*k - 6 2 = 1/2*k - 6 8 = 1/2*k k = 16

3 Answers · Science & Mathematics · 02/03/2009