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I'll express the force as F =

**k**Qq / d² where**k**= 1/4πε₀ = 8.99e9 N·m²/C² Both q1 and q2 will...1 Answers · Science & Mathematics · 27/09/2020

... m2/r^2) b is the correct answer. 2. You can equate h nu=

**k**_b T.**k**_b is the Boltzmann constant, T is the...1 Answers · Science & Mathematics · 28/09/2020

... on the threshold of slipping, then Ff = 254 N = µ

**k***m*g*cosΘ = µs * 43**k**g * 9.8m/s² * sin37º means...1 Answers · Science & Mathematics · 24/09/2020

...net force = applied force horizontal - friction force m*a = Fx - µ

**k***(Fy + m*g) 8.67**k**g * -0.90m/s² = 20N - µ**k***(25N...1 Answers · Science & Mathematics · 23/09/2020

using

**k**inematics, a = g*(sinΘ + µ**k***cosΘ) a = 9.81m/s²*(sin15.0º + 0.18*cos15.0º) = 4.24...2 Answers · Science & Mathematics · 23/09/2020

1.381e-23J/

**K*** T = 1.6e-19 J T = 11,586**K**So one might conclude that 1 eV of energy is quite a bit for a single particle. If you find this helpful, please select Favorite Answer!1 Answers · Science & Mathematics · 22/09/2020

When periodic, assume a sin wave type solution. s= a sin kt.

**k**is the time constant. s is the strain. s1=0.0032 = a sin kt1, s2 = a sin...3 Answers · Science & Mathematics · 22/09/2020

a. intensity I = p*v where pressure p = B*

**k***A*sin(**k**x - ωt) and velocity v = A*ω*sin(**k**x - ωt) (see citation) so...1 Answers · Science & Mathematics · 20/09/2020

... * 20

**K**= 896 J since for CHANGES in temperature, 1**K**= 1 ºC 8) ΔQ = 3kg * 4186J/kg·ºC * ...1 Answers · Science & Mathematics · 20/09/2020

type of steel is needed. I'll guess at 12e-6 /

**K**∆L/L = α∆T 0.19/L = 12e-6(42– –9) L = 0...3 Answers · Science & Mathematics · 18/09/2020

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