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Assuming that the pressure does not change, V1/T1 = V2/T2 200 L / 20

**K**= V2 / 40**K**V2 = 400 L2 Answers · Science & Mathematics · 10/09/2020

rate=

**k**[A]x [B]y from data 6.00=**k**[0.200]x [0.1]y ------------->(1) 1.50=**k**[0.1]x [0.1]y...2 [2]^x = (2)² , x = 2 from trial 1 and 3 α1/α3 =**k**[0.200]x [0.100]y/**k**[0.200]x [0.200]y= 6.00 × 10–2/1.20...1 Answers · Science & Mathematics · 10/09/2020

Your answer is correct. Potassium carbide is an ionic compound containing potassium ions (

**K**⁺) and carbide ions (C₂²⁻), and its formula is**K**₂C₂.1 Answers · Science & Mathematics · 13/09/2020

Coulomb's Law is F =

**k**(q1q2/r^2) where**k**= 9.0X10^9 N m^2/C^2 F = 9...2 Answers · Science & Mathematics · 23/08/2020

...^-2) = (8.10X10^4 J/mol / 8.314 J/molK) (1/292

**K**- 1/338**K**) ln (k2/2.50X10^-2) = 4.541 k2/2.50X10^-2 = e^4...1 Answers · Science & Mathematics · 28/08/2020

Given, t1/2 = 4.1hr For a first order reaction,

**k**= 0.693/t1/2 So,**k**= 0.693/4.1**k**= 0.169hr-1 Further ...1 Answers · Science & Mathematics · 10/09/2020

... 0.983 atm (0.0107 L) = n (0.08206 Latm/molK)(304

**K**) n = 4.216X10^-4 mol CO2 From the balanced equation...1 Answers · Science & Mathematics · 16/09/2020

...x 58.4 grams/mole = 146.1 g %(W/V) 146.1/1000ml = 14.6%

**K**) Firstly molar mass of NaCl is calculated then ...1 Answers · Science & Mathematics · 24/08/2020

... ln Keq -3810 J/mol = -(8.314 J/molK) (298.15

**K**) ln Keq Keq = 4.65 Keq = [C]/[A][B] = 4...1 Answers · Science & Mathematics · 15/09/2020

Potassium is a chemical component with the symbol

**K**(19). Potassium is a mineral found in the foods that we eat.Potassium also an electrolyte.3 Answers · Science & Mathematics · 19/09/2020

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