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  1. The curly delta means the same thing as the "d". I agree that the whole expression APPEARS to mean the same thing as the integral from x = 1 to 2 of  (x^3 - 16 + 64/x^3) dx which would be (1/4)x^4 - 16x - 32/x^2, to be evaluated at x = 2 and 1, which comes out to (1/4)16 - 32 - 8 - (1/4...

    1 Answers · Science & Mathematics · 03/02/2021

  2. 66% off ==> 244.80 = (1- 66/100)* x where x is the original (before the 66% reduction) price so x = 24480/34  (NOT x = 24480/66) ==> x = $720

    4 Answers · Science & Mathematics · 01/10/2020

  3. Yes, the quadratic formula can be used to solve ax²ⁿ + bxⁿ + c = 0. Note, however, that it cannot be used in the example that you gave, because 0.954/0.478 ≅ 1.996, not 2.

    2 Answers · Science & Mathematics · 15/07/2020

  4. Assuming that the figure is a rhombus; then z + 6 = 3z + 2 so 2z = 4 and z = 2 and 7a + 5 = 5a + 9 so 2a = 4 and a = 2 Update if you need more, and please choose  a best answer from among those you get.

    2 Answers · Science & Mathematics · 28/11/2019

  5. y = mx + c... m = rise/run = change in y / change in x = (80-62)/(6-0) = 18/6 = 3 so we have y = 3x + c when x = 0, y = 62 ==> c = 62 so, yes you are right --- y = 3x + 62

    1 Answers · Science & Mathematics · 15/03/2018

  6. One can know a lot by inspecting the magnitude of A and B | B | = | I K | usually >> | A | = | I + K | So as | B | is big, | 6 B | is even bigger As 6 B = J+A...

    3 Answers · Science & Mathematics · 01/12/2017

  7. "slightly bad at algebra" ...so you should be taking intermediate algebra, instead of this class. You have reached too far, and you are paying the price. You will probably pass this class, but not well enough to get into the calculus class you are aiming for. I...

    3 Answers · Science & Mathematics · 29/10/2017

  8. We're given: RS = 5x+17 ST = 8x-31 S is the midpoint of line RT So,      RS = ST            ← By the definition of midpoint 5x+17 = 8x-31        ← By substitution ... Now, solve for x 17+31...

    3 Answers · Science & Mathematics · 04/09/2017

  9. Midpoint of (x₁, y₁), (x₂, y₂) is ((x₁+x₂)/2, (y₁+y₂)/2) X = (x, y) Y = (0, 2) Midpoint = ((x+0)/2, (y+2)/2) = (3,−5) (x+0)/2 = 3 (y+2)/2 = −5 Solve for x and y

    3 Answers · Science & Mathematics · 04/09/2017

  10. ...gt; e^(z+w) = e^z <==> e^w = 1 <==> w = 2π ik for any integer k. ---- For the last step, writing w = x + iy for real...

    2 Answers · Science & Mathematics · 07/08/2017

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