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...all equal magnitudes. In fact, there's no need for any 'origin' to frame the problem; it sure

**does**help when you're trying to work out the answer, though! The net force vector is just the vector...1 Answers · Science & Mathematics · 03/12/2012

... you know how much I hate physics? Lol I hate it with a PASSION. **

**Do**sig figs matter? Lol The equation? Energy / volume = (1/2)(epsilon)E^2 ? ...IDK...2 Answers · Science & Mathematics · 10/09/2010

work

**done**= force x distance mg =**1**.**99**x 9.8 = 19.502 N 19.502 x 0.128 = force required to overcome friction = 2.5 N (rounded) 0 - 2.5 = -2.5 N (force of friction) -2.5 x 1.09 = -2.725 J (answer)2 Answers · Science & Mathematics · 19/03/2011

If you

**did**not specify that each hinge supports half of the doors weight, this question...2 Answers · Science & Mathematics · 31/07/2009

...mg = mv²/r => T = m(v²/r - g) = 3.21(10.7²/

**1**.**99**- 9.81) = 3.21*47.723 = 153.19 N also at loop low: T - mg = mv²...2 Answers · Science & Mathematics · 22/05/2015

What formula

**did**you use? In simplest form, Kepler's Third ...3 Answers · Science & Mathematics · 04/03/2014

The friction is given by Ff = mu*N = mu*m*g Work is the force times the distance . (Ff in this case)*(

**1**.09m in this case)2 Answers · Science & Mathematics · 14/05/2011

Use just

**1**cable tension and**1**/2 the angle, to determine the normal force in the forward direction. (cos 10.2) x 5140N = 5058.788N. Double it, = net force in forward direction of 10,117.58N. W = (fd), = 10,117.58 x**1**,999m, = 20,225,042.42 joules., or 20.225MJ.1 Answers · Science & Mathematics · 23/09/2012

...v^2 = 0.012027 v = sqrt(0.012027/0.00305) =

**1**.**99**m/s What values**did**you put for (normal force)(coefficient of friction)(distance) ? _______________.2 Answers · Science & Mathematics · 02/12/2010

lol is this a trick question or lame?? water between 0.

**1**-**99**.9 degrees celcius doesn't boil kept as it is...22 Answers · Science & Mathematics · 17/02/2008