The amount of work needed to lift engine is its change in potential energy a) mgh = (170)(9.81)(2.2) = 3770 J b) the amount of work done by the team is Fd = 1720(2.2) = 3785 J c) e = 3770/3785 =

**99**.6%2 Answers · Science & Mathematics · 26/11/2020

...see below. equate two angular momentums and solve for ω₂ I₁ω ₁ = I₂ω₂ (you did ask for how, not for the solution) ω = V/r ω is angular velocity in...

3 Answers · Science & Mathematics · 14/11/2018

...the moon as decelerating it. There is a small amount of work done due to tidal effects, but we were not asked to consider those.

1 Answers · Science & Mathematics · 25/02/2018

... (difference in potential) * (moving charge) = (543.8 V)(- 1 .60×10^-19 C) = -8.70×10^-17 J This is... the electron in the direction that it's going, and doing positive work.

1 Answers · Science & Mathematics · 24/02/2018

KEi = PEelf

**1**/2mvi^2 = Ke x q1 x q2 / d e =**1**.6 x 10^-19 C Ke = 8.**99**x 10^9 d = 2Ke x q1 x q2 / mvi^2 Plug and play... Ans =**1**.90 x 10^-141 Answers · Science & Mathematics · 30/11/2017

... height = ut -

**1**/2 gt^2 = (31.262)(3.19) -**1**/2(9.8)(3.19)^2 =**99**.72578 - 49.6289 = 49.86289 = 49.86 m3 Answers · Science & Mathematics · 09/11/2016

... just 2*tmax - it takes just as long to fallback as it

**does**to rise up so the total travel time is T = 2*tmax...x = v0x*T = v0*cos(q)*2*v0*sin(q)/g = v0^2*sin(2q)/g =**1**.**99**m away from Luna1 Answers · Science & Mathematics · 26/09/2016

...13.75m so if its 13.75m behind it will brake at the same spot the lead car did and they will stop at the same spot.

3 Answers · Science & Mathematics · 17/01/2016

Horizontal V component = (cos 45*23.4) = 16.5463 m/sec. KE at top of trajectory=

**1**/2 (mv^2) = 135.52 Joules. It has only horizontal V at the top of its trajectory.1 Answers · Science & Mathematics · 15/10/2015

A) Universal law of gravitation: F = GMm/R^2 F = mg = GMm/R^2 => M = gR^2/G Calculate gravitational acceleration of the planet: v = v0 - gt The mass of the stone is irrelevant, it reaches the...

1 Answers · Science & Mathematics · 11/09/2015