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  1. ...4.9*t^2 -1.99=-4.9*t^2 t=.637seconds Now with the time all you have to do is figure what speed an object needs to travel 3.1m in .637 sec. .637...

    4 Answers · Science & Mathematics · 25/03/2008

  2. .... we have x+X = 5.79*10^10, and (G*3.18*10^23)/x = (G*1.99*10^30)/X or 3.18/x = (1.99/X)10^7 or (1.99*10^7)x = 3.18*(5.7...

    2 Answers · Science & Mathematics · 31/03/2010

  3. only work done is in horizontal direction, 1 atm = 101.3 kPa, W = F * d cos (theta) P = F d = 1 L theta = 0 W = 101.3(1)(1) = 101.3 J

    2 Answers · Science & Mathematics · 29/04/2009

  4. 1. pbefore = (5.5kg)(18.1) = -99.55kg*m/s, pafter = (5.5kg)(10) = 55kg*m/s pafter = pbefore, but in your case it isn't...since the sidewalk doesn't move...sorry I am a bit confused by this one as well. .

    1 Answers · Science & Mathematics · 28/07/2009

  5. ... (8.65 N + 1.84 S) = 6.81 N (7.01 W + 1.99 E) = 5.02 W now draw these, make a parallelogram and solve for the diagonal...

    1 Answers · Science & Mathematics · 01/09/2012

  6. ...α)(9.43)^2 Solving for "α" α = 2(14.1*2π)/9.43^2 α = 1.99 rad/sec^2 Hope this helps.

    3 Answers · Science & Mathematics · 22/07/2009

  7. ...direction as acceleration. x=1/2gt^2+vt 51.1 m = 1/2*9.81 m/s/s *t^2 + v t t = 1.99 s 51.1 m = 19.42 m + 1.99 v v= 15.9 m/s

    1 Answers · Science & Mathematics · 24/04/2008

  8. 1.99 * 10 ^-3 kg /(s*m) = x 1 kg = 1000 grams 1 kg * x = 1.99 * 10^-3 kg 1000 grams/(s*m) Divide by kg x = 1.99 grams...

    2 Answers · Science & Mathematics · 07/03/2010

  9. work = force x distance 379 x 1.99=754.21j

    2 Answers · Science & Mathematics · 12/04/2010

  10. The work done (by car's engine) to take car up hill = 6.74E5...

    1 Answers · Science & Mathematics · 26/11/2013

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