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  1. ...you don't know this notation). Some of the terms look like: (x+ 1 )^ 100 = ( 100 , 100 ) x^ 100 + ( 100 ,99) x^99 + ( 100 ,98) x^98 + ... + ( 100 , 1 ) x + ( 100 ,0) = 100 ...

    6 Answers · Science & Mathematics · 12/09/2012

  2. ... .01 (hence 1 /.01) is the same as multiplying 100 (hence 1 * 100 ). 1 * 100 = 100

    1 Answers · Science & Mathematics · 17/02/2010

  3. 1 + 2 + 3 + ... + 98 + 99 + 100 = 1 + 100 + (this is the 1st row) 2 + 99 + 3 + 98... Another way. Let (A) 1 + 2 + 3 + .... 98 + 99 + 100 = S (there are 100 numbers being...

    4 Answers · Science & Mathematics · 10/02/2009

  4. ...anything with that? Yes. FOIL the (x+ 1 )(x+ 1 ) Multiplication... do you have any of that? Yes, you have a 4 that.... Then you will be able to move the 100 over to the other side, having your equation...

    2 Answers · Science & Mathematics · 13/09/2011

  5. ∫( 1 / 100 )[ e^(y/ 100 ) ]dy = ( 1 / 100 ) ∫[ e^(y/ 100 ) ]dy Now, ∫(e^y)dy = e^y. So,( 1 / 100 ) ∫[ e^(y/ 100 ) ]dy = ( 1 / 100 ) [e^(y/ 100 )] / ( 1 / 100 ) + c Since 1 / 100 ...

    3 Answers · Science & Mathematics · 06/03/2008

  6. Percent is over 100 so ( 1 / 100 )/ 100 = 1 / 100 * 1 / 100 = 1 /10,000

    1 Answers · Science & Mathematics · 14/09/2012

  7. 0.0D is not multiplication. For instance, if D is 2, 0.0D is 0.02. If D is 9, 0.0D is 0.09. So if you multiply top and bottom of 1 /(0.0D) by 100 you get 100 /D.

    1 Answers · Science & Mathematics · 20/04/2012

  8. You're right. It diverges. All you have to do is prove that 1 + 1 /2 + 1 /3 + .... is divergent and you've got it. The ...

    5 Answers · Science & Mathematics · 03/03/2014

  9. y = [ (x^10)* (91x - 34)^( 1 /2) ] / (x - 1 )^ 100 Take "ln" of both sides: ln... 1 /y)dy = 10( 1 /x)dx + ( 1 /2)(91)( 1 / (91x - 34))dx - 100 ( 1 /(x - 1 ))dx ( 1 /y)dy = [(10/x) + (91/ (182x - 68)) - ( 100 /(x...

    1 Answers · Science & Mathematics · 12/03/2008

  10. ... can travel up to half the speed of light. 300,000 Km/s ÷ 2 ÷ 100 = 1 ,500 Km. Sound works best.

    4 Answers · Science & Mathematics · 17/08/2008

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