Yahoo Web Search

  1. Sort by

  1. Here is a lot of them, but not all: 1 = (4 / 4) * (4 / 4) 2 = (4 / 4) + (4 / 4) 3 = (4 + 4 + 4) / 4 4 = (4 - 4) * 4 + 4 5 = ((4 * 4) + 4) / 4 6 = sqrt(4) * (4 - (4 / 4)) 7 = 4 + 4 - (4 / 4) 8 = (4 + 4) * 4 / 4 9 = 4 + 4 + (4 / 4) 10 = (44 - 4) / 4 11 = 4^2 - 4 - (4 / 4) 12 = 4 * (4 - (4 / 4)) 13 = 44 / 4 + sqrt(4) 14 = 4 * 4...

    3 Answers · Computers & Internet · 17/11/2010

  2. %random% will generate a random number 0-32767. To get 0-100 use following code: @echo off set /A r=%RANDOM% %% 100 + 1 echo %r%

    4 Answers · Computers & Internet · 12/11/2010

  3. ...1,2}; int numbers[5] = {1,2,4,7,9}; So you could theoretically do that with 100 numbers. However, this would be very long and is...

    3 Answers · Computers & Internet · 26/10/2008

  4. ...to screen get( 'rpt' ).innerHTML = msg; } // or, if you just have to do it by {for}... function calcMult2() { // get number for which to find...

    4 Answers · Computers & Internet · 08/12/2008

  5. All you have to do is change the "annotation scale" which is usually found at the bottom right or left corner.

    2 Answers · Computers & Internet · 16/09/2009

  6. Not sure how you want it formatted but the following will work. for ($x=1; $x<=100; $x++) {   if ($x == date("i")) {echo   '<u>'.$x.'</u> ';}   else {echo $x.' ';} } *Editited, yahoo...

    1 Answers · Computers & Internet · 30/10/2008

  7. ...the code so in my head it generates a random number between 1-100 then i would use a check if guess = Rand num cout if guess is...

    2 Answers · Computers & Internet · 27/05/2010

  8. if you know how to make flowcharts, then those problems are easy. use diamond symbol for decision, use rectangle for operation/action like print something, add two numbers, etc. use arrows for the control of flow.

    1 Answers · Computers & Internet · 03/11/2008

  9. ..., I'll give you a brief explanation of a method to do this. After I have done this, you should... is divisible by the number 1. You do this by checking whether there's a remainder...

    1 Answers · Computers & Internet · 03/11/2012

  1. Try asking your question on Yahoo Answers